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  1. Conservation of momentum in x direction m₁ux₁ + m₂ux₂ = (m₁+m₂)vx vx = (m₁ux₁ + m₂ux₂)/(m₁+m₂) vx = [(41.2 kg)(1.68 m/s) + (45.3 kg)(0)] / (41.2 kg + 45.3 kg) vx = 0.800 m/s Conservation of momentum in y direction...

    3 Answers · Science & Mathematics · 27/11/2020

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