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V = k(3Âµ)/0.14 = 193000 volts Potential from a charge is V = kQ/r in volts Â Â k = 1/4Ï€Îµâ‚€ = 8.99e9 NmÂ²/CÂ² Â Â r is separation in meters Â Â q is charge in coulombs

1 Answers Â· Science & Mathematics Â· 09/02/2020

Check your arithmetic.Â I get -1.62*10^-11C

1 Answers Â· Science & Mathematics Â· 05/02/2020

The initial electric potential energy is U = kQq / d U = 8.99e9NÂ·mÂ²/CÂ² * -8.50e-9C * -1.6e-19C / (0.325m) U = 3.76e-17 J and this gets converted into KE in the electron: KE = 3.76e-17 J...

1 Answers Â· Science & Mathematics Â· 09/02/2020

V = Î»*f = 0.82*4 = 3.28 m/sec

2 Answers Â· Science & Mathematics Â· 05/02/2020

density Âµ = EÂ² / Îµâ‚€ so EÂ² = Âµ*Îµâ‚€ = 5500J/mÂ³ / 8.85e-12 CÂ²/NÂ·mÂ² = 6.2e14 NÂ²/CÂ² E = 2.5e7 N/C then E = Ïƒ / Îµâ‚€ = Q / AÎµâ‚€ Q = EA...

1 Answers Â· Science & Mathematics Â· 01/02/2020

moles ethanol = 1.50 g / 46.07 g/mol = 0.03256 mol PV = n RT P = nRT/V P = 0.03256 mol (0.08206 Latm/molK) (523 K) / 0.251 L P = 5.56 atm If you need pressure in a different unit, just use the R that...

1 Answers Â· Science & Mathematics Â· 10/02/2020

...? Calculate area and multiply fo thickness.Â Although 5

**cm**is much too thick for paint. area of hemisphere is 2Ï€rÂ² = 2Ï€...3 Answers Â· Science & Mathematics Â· 09/02/2020

spring energy = work done + final KE Â½kdÂ² = Âµk*m*g*0.050m + Â½mvÂ² When I plug in your values I get d = 0.107 m which should be rounded to 0.11 m = 11

**cm**1 Answers Â· Science & Mathematics Â· 07/02/2020

...course, you know that the gradient is not 10.6 but 10.6

**cm**/s^2. Assuming: t is the elapsed time...see the gradient is 0.5a Hence, if 0.5a = 10.6**cm**/s^2 a = 21.2**cm**/s^2 If we extrapolate the graph to t...1 Answers Â· Science & Mathematics Â· 08/02/2020

(94.8 g) / (1.5 g/

**cm**^3) / (5.18**cm**^2) = 12.2**cm**1 Answers Â· Science & Mathematics Â· 07/02/2020

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