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  1. V = k(3µ)/0.14 = 193000 volts Potential from a charge is V = kQ/r in volts    k = 1/4πε₀ = 8.99e9 Nm²/C²    r is separation in meters    q is charge in coulombs

    1 Answers · Science & Mathematics · 09/02/2020

  2. The initial electric potential energy is U = kQq / d U = 8.99e9N·m²/C² * -8.50e-9C * -1.6e-19C / (0.325m) U = 3.76e-17 J and this gets converted into KE in the electron: KE = 3.76e-17 J...

    1 Answers · Science & Mathematics · 09/02/2020

  3. density µ = E² / ε₀ so E² = µ*ε₀ = 5500J/m³ / 8.85e-12 C²/N·m² = 6.2e14 N²/C² E = 2.5e7 N/C then E = σ / ε₀ = Q / Aε₀ Q = EA...

    1 Answers · Science & Mathematics · 01/02/2020

  4. moles ethanol = 1.50 g / 46.07 g/mol = 0.03256 mol PV = n RT P = nRT/V P = 0.03256 mol (0.08206 Latm/molK) (523 K) / 0.251 L P = 5.56 atm If you need pressure in a different unit, just use the R that...

    1 Answers · Science & Mathematics · 10/02/2020

  5. ...? Calculate area and multiply fo thickness.  Although 5 cm is much too thick for paint. area of hemisphere is 2πr² = 2π...

    3 Answers · Science & Mathematics · 09/02/2020

  6. spring energy = work done + final KE ½kd² = µk*m*g*0.050m + ½mv² When I plug in your values I get d = 0.107 m which should be rounded to 0.11 m = 11 cm

    1 Answers · Science & Mathematics · 07/02/2020

  7. ...course, you know that the gradient is not 10.6 but 10.6 cm/s^2. Assuming: t is the elapsed time...see the gradient is 0.5a Hence, if 0.5a = 10.6 cm/s^2 a = 21.2 cm/s^2 If we extrapolate the graph to t...

    1 Answers · Science & Mathematics · 08/02/2020

  8. (94.8 g) / (1.5 g/cm^3) / (5.18 cm^2) = 12.2 cm

    1 Answers · Science & Mathematics · 07/02/2020

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