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  1. I assume that "10 cm size" means a perimeter of 10 cm . The internal angles of...1*cos108º = 2.618 cm² by the law of cosines c = 1.618 cm so the semiperimeter is s = ½(1.618 + 1 + 1) cm = 1.809 cm ...

    2 Answers · Science & Mathematics · 18/09/2020

  2. ... and CD are the parallel sides with lengths 10 cm and 20 cm , respectively. See the attached sketch. Let point ...

    3 Answers · Science & Mathematics · 03/08/2020

  3. a) at 14 cm , the "enclosed" charge is Q = 50nC * (14/30... * 5.08e-9C / (0.14m)² = 2331 N/C (outward) b) at 37 cm , the enclosed charge is 50 nC: E = 8.99e9N·m²...

    1 Answers · Science & Mathematics · 30/09/2020

  4. ...7=1.8097x 10^-5T In the smaller loop, the radius = r1 = 12.5 cm = 0.125 m I1 = 3.6 Amp hence magneti field at the center = B1...

    1 Answers · Science & Mathematics · 14/05/2020

  5. displacement = 20 cm - (- 20cm) + (- 10 cm ) = 30 cm distance covered = |(-20cm) - (20cm)| + |(-10cm) - (-20 cm )| = 40cm + 10cm = 50 cm

    1 Answers · Science & Mathematics · 05/07/2020

  6. add 5 zeroes to the right side of the number. 1000 (km/m) x 100 ( cm /m) = 100,000 ( cm /km). five zeroes.  follow the units.

    6 Answers · Science & Mathematics · 01/07/2020

  7. The area of a sector of a circle with a radius of 15 cm is 75pi cm ^2. ? Total circle Area = π(15)^2 = 225π cm ^2...

    11 Answers · Science & Mathematics · 28/05/2020

  8. The density of solid titanium is 4.506 g/ cm ^3. There is a very small difference for temperature and pressure ... very small...

    3 Answers · Science & Mathematics · 03/11/2020

  9. A=4.14 cm V=3.59 V=f*λ V/λ=(A*2*pi*f)/(f*I) 3.59=(2*A*pi)/I I=(2*4.14*pi)/3.59 I=7.24

    1 Answers · Science & Mathematics · 08/07/2020

  10. ...)/(u₁+u₂) = (6.5*22 + 14*(-15))/(6.5 + 14) = -3.27 cm /s Initial vel. of 6.5g object in CoMF = 22 - (-3.27) = 25.27 cm /s...

    1 Answers · Science & Mathematics · 18/06/2020

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