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cos(35°) = x/20 20 cos(35°) = x --> 16.38

**cm**(approximation).2 Answers · Science & Mathematics · 18/05/2019

A = pi * (107/2)^2 a = pi * (107/2)^2 * (90/360) - (1/2) * (107/2) * (107/2) * sin(90) (A - 2a) / A => (pi * (107/2)^2 - 2 * pi * (107/2)^2 * (1/4) + (107/2)^2 * 1) / (pi * (107/2)^2) => (107/2)^2 * (pi - pi/2 + 1) / (pi * (107/2)^2) => (pi/2 + 1) / pi => ((pi + 2) / 2) / pi => (pi + 2) / (2pi) Multiply that by 100...

2 Answers · Science & Mathematics · 15/06/2019

d sin θ = m λ For small θ, sin θ ≈ tan θ. tan θ = (0.00310 / 2) / 0.510 d * (0.00310 / 2) / 0.510 = (679x10^-9) d =

2 Answers · Science & Mathematics · 15/03/2019

a) 2*pi*15*(100/360) = (25/3)*pi =~ 26.179938779914943653855361527329 m b) pi*(20^2)*(65/360) = (650/9)*pi =~ 226.89280275926284500007979990352 m^2

1 Answers · Science & Mathematics · 20/06/2019

System energy is constant, so any spring potential energy released will show up as kinetic energy ½mv² = ½kA² - ½k(A/2)² mv² = k(A² - (A/2)²) v² = k/m(A² - (A/2...

2 Answers · Science & Mathematics · 10/07/2019

1) F = vector Σ kQq / d² F = 2*8.99e9N·m²/C²*-3.00e-6C*9.00e-6C*cos45º/(0.0600m)² F = -95.4 N where the negative sign indicates "attraction." The magnitude is 95.4 N 2...

1 Answers · Science & Mathematics · 09/02/2020

KE(0) = ½*0.8*0.3² = 0.036J ½kx² = ½*18*x² = 0.036 x² = 2*0.036/18 = 0.004 = 0.06325² A = 6.3cm <<<<< A) ω...

1 Answers · Science & Mathematics · 18/09/2019

ω² = 10/0.1 = 100 so ω = 10 ½kx² = ½*10*A² = 5*A² = ½*0.1*V² = ½*0.1*0.15² = 1125µJ ωA = Vmax = 0.15 = 10*A so A = 0.015 = 15mm x = 0.015*cos10t...

1 Answers · Science & Mathematics · 10/07/2019

Work per stroke: W = F d = m g d Power = Work per stroke / time per stroke P = W/t = m g d / (1/f) = m g d f = 0.00400kg * 9.81N/kg * 0.0342m * 65.0/s = 87.2 mW

2 Answers · Science & Mathematics · 23/10/2019

These would be some frighteningly large ladybugs. This problem is really just an exercise in calculating moments of inertia. The bugs are easy -- they can be treated as point masses. Bug 1: I1...

2 Answers · Science & Mathematics · 05/11/2019

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