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  1. ... and CD are the parallel sides with lengths 10 cm and 20 cm , respectively. See the attached sketch. Let point ...

    3 Answers · Science & Mathematics · 03/08/2020

  2. ...7=1.8097x 10^-5T In the smaller loop, the radius = r1 = 12.5 cm = 0.125 m I1 = 3.6 Amp hence magneti field at the center = B1...

    1 Answers · Science & Mathematics · 14/05/2020

  3. displacement = 20 cm - (- 20cm) + (- 10 cm ) = 30 cm distance covered = |(-20cm) - (20cm)| + |(-10cm) - (-20 cm )| = 40cm + 10cm = 50 cm

    1 Answers · Science & Mathematics · 05/07/2020

  4. 1 cubic meter = 10^6 cubic cm 0.014 kg/ cm ^3 * 3.5 * 10^6 cm ^3 => 3.5 * 0.014 * 10^6 kg => 3.5 * 1.4 * 10^(-2) * 10^(6) kg => 3.5 * 1.4 * 10^(4) kg => (7/2) * (7/5) * 10^4 kg => (49/10) * 10^4 kg => 4.9 * 10^4 kg 49000 kg

    3 Answers · Science & Mathematics · 31/08/2019

  5. add 5 zeroes to the right side of the number. 1000 (km/m) x 100 ( cm /m) = 100,000 ( cm /km). five zeroes.  follow the units.

    6 Answers · Science & Mathematics · 01/07/2020

  6. ... have to guess. I am guessing that r = 2.18 +- 0.100 cm and that m = 122.3 +- 0.7 g so to do it formally take the smallest mass...

    1 Answers · Science & Mathematics · 31/08/2019

  7. The area of a sector of a circle with a radius of 15 cm is 75pi cm ^2. ? Total circle Area = π(15)^2 = 225π cm ^2...

    11 Answers · Science & Mathematics · 28/05/2020

  8. A=4.14 cm V=3.59 V=f*λ V/λ=(A*2*pi*f)/(f*I) 3.59=(2*A*pi)/I I=(2*4.14*pi)/3.59 I=7.24

    1 Answers · Science & Mathematics · 08/07/2020

  9. ...)/(u₁+u₂) = (6.5*22 + 14*(-15))/(6.5 + 14) = -3.27 cm /s Initial vel. of 6.5g object in CoMF = 22 - (-3.27) = 25.27 cm /s...

    1 Answers · Science & Mathematics · 18/06/2020

  10. ...*4.92e-3m = 4.96e13 m²/s² and V = 7.05e6 m/s = 7.05e8 cm /s Actually, we don't need the velocity V. We need the...

    2 Answers · Science & Mathematics · 08/09/2019

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