**cm to mm**=**cm**multiplied by 10**cm to**km=**cm**divide by 1000**cm to**m =**cm**divide by 100 ml**to**kl=ml divide by one million4 Answers · Science & Mathematics · 25/10/2010

well, you know that there are 10

**mm**in 1**cm**. so when u set up ur equation.... 5cm/1 x 10mm/1cm --> the**cm**will cancel out, multiply the numerator 50mm1 Answers · Science & Mathematics · 21/02/2009

1

**cm**= 10**mm**1 m = 100**cm**1 km = 1000 m you can do the rest1 Answers · Science & Mathematics · 27/08/2008

...on the

**cm**rule and determine the diameter in**cm**...muiltiply the c reading by 10**to**get the number of**mm**. Alternatively you can place the**cm**rule directly on the gel but this can be messy....4 Answers · Science & Mathematics · 16/04/2009

K H Da B D C M

6 Answers · Science & Mathematics · 30/08/2008

...easily do the rest on your own, but here are the answers for you

**to**check with. 2000 um = 2**mm**12**cm**= 120000 um 50 um = 50000 nm 40 a = 4 nm 100 nm = 0.1 um 750 nm = 0.00075**mm**0...1 Answers · Science & Mathematics · 21/09/2010

micrometer, because that's the scale of the objects that you are generally looking at under a microscope. kind of like if you are measuring a pencil, you would probably use

**cm**rather than meters or km.2 Answers · Science & Mathematics · 05/07/2010

1

**cm**^3 = 1000**mm**^3 therefore 100mm^3 = (1/10)**cm**^3 10^10 bacteria/**cm**^3 = 10^9 bacteria/ 100mm^3 it must therefore be diluted by one 10th (9:1) a total of 7 times, Or 10^7, total dilution factor.2 Answers · Science & Mathematics · 26/10/2010

a) 2.725 - 3.25

**cm**b) 1.225 - 2.72**cm**c) 3.25**mm**- 1.225**cm**As you are trying**to**make a timeline, can you tell me the length of your timeline? For...2 Answers · Science & Mathematics · 01/07/2010

### if the lenghts of a spermatozoid is 0.006

**mm**, how can 100 millions of them fill into 1 ml of sperm?One ml = 1 cubic

**cm**, 1**cm**= 10mm, 10mm^3 = 1,000 cubic**mm**If,**to**make things simple, we round .006mm**to**.01, and we assume that the ...3 Answers · Science & Mathematics · 30/04/2007