Yahoo Web Search

  1. Assume a 100 g sample of the gas- 64. 81 g C = 5 .396 mol C atoms 13.60 g H = 13.493 mol...57 g / molar mass molar mass = 74.8 Molecular formula = C4 H10 O

    1 Answers · Science & Mathematics · 08/01/2011

  2. ...start with Imperial. :D C - 64. 81 % / 12.01 = 5 .396 H - 13.60% / 1.01 = 13.465 O - 21... your imperial equation is C4 H10 O Now Gas ...

    1 Answers · Science & Mathematics · 15/03/2011

  3. ... chemical equation for (a) the complete combustion of butyric acid, H C4 H7 O2 (I) & 5 O2 (g) -- 4 CO2 (g) & 4 H2O (l or g...

    2 Answers · Science & Mathematics · 03/09/2008

  4. ...0.0004768 we divide by the smallest number C2 H 1. 5 O we multiply by 2 C4 H3O2 ( Molar mass = 83 g/mol) molar mass compound = 52.3 / 0.315 =166...

    1 Answers · Science & Mathematics · 22/10/2008

  5. ... x 12 g/mole = 20.4 g C 23. 5 g H2O x 1 mole H2O/18...76.98 g O x 1 mol/16 g = 4. 81 moles O So, you...whole numbers, multiply by 4 to get C4 H6 O11 = EMPIRICAL...

    2 Answers · Science & Mathematics · 15/12/2016

  1. Try asking your question on Yahoo Answers