C4 frequency = 261.626 Hz Assuming that a 0.81m string accommodates λ/2 when vibrating .. .. λ = 1 .62 m Wave velocity along the string, v = f x λ .. v = 261.626Hz x...
1 Answers · Science & Mathematics · 08/10/2011
1 . 1 /15 2. 81 3. B⁹ 4. b²/ c⁴ 5. x+17 6. √ x² 7. ½√x 8. 94(2x) 9. x⁶ 10. 6...
5 Answers · Science & Mathematics · 02/03/2013
i like the first one. hope i helped:)
6 Answers · Beauty & Style · 07/12/2009
...27 • 3!) = 1 / 81 = 1 /(3^3 • 3) f(4)(x) = -6/(x + 3)^4.......f(4)(0) = -6/ 81 ........ c4 = -6/( 81 • 4!) = - 1 /324 = - 1 /(3^4 • 4) cn = (- 1 )^(n - 1 ) 1 /(3^n • n) for n > 0
2 Answers · Science & Mathematics · 28/04/2010
There are 3 things your engine needs to run, spark, fuel, air. You are not getting at least one of these in the correct amount for some reason. Start with spark plugs and wires and ignition. Make sure all your ignition...
2 Answers · Cars & Transportation · 17/09/2010
... , c2=5.89uF , c3=7.45uF , c4 =3.36uF , v=15V c12= 1 .08+5.89= 6.97uF (Parallel) c34... (Parallel) c1234= (6.97*10. 81 )/(6.97+10. 81 )= 4.2377uF (Series...
1 Answers · Science & Mathematics · 21/02/2014
... 1 /3)(-2/3)(-5/3)(-8/3)/4! x^4... C0 = 1 C1 = 1 /3 C2 = - 1 /9 C3 = 5/ 81 C4 = -10/243
1 Answers · Science & Mathematics · 02/03/2014
...3) = 399 f(-2) = -16 f(- 1 ) = - 1 f(0) = 6 f( 1 ) = - 1 f(2) = -76 f(3) = - 81 f(4) = 1274 By Intermediate Value Theorem, there exist a value c1, c2, c3, c4 in the interval (-3, -2), (- 1 , 0), (0, 1 ) and (3, 4) respectively...
1 Answers · Science & Mathematics · 20/11/2010
... C2 C3 C4 C5 Total 1 21 18 19 16 14 88 [actual count...0.132 3 16 18 16 18 13 81 18.04 16.45 16.77 16.14 13.61 0...
1 Answers · Science & Mathematics · 11/05/2008
