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...39;s a pretty healthy drive but well worth it ie., boating , fishin' annnnd ya' be so close to the town....google.com/maps?saddr=Livermore% 2C +CA.&daddr=37.0510763144% 2C -121.08987173...
1 Answers · Sports · 14/07/2007
...of the boat to the dock C = length of rope that is pulling the boat Differentiating the above, 2A(dA/dt) + 2B(dB/dt) + 2C (dC/dt) Since A = 6 ft (constant), dA/dt =0 dB...
1 Answers · Science & Mathematics · 16/04/2008
...know a^2 + b^2 = c^2 derivative: 2a*da/dt + 2b*db/dt = 2c *dc/dt (divide by2) (1)(0) +(8)db/dt = (sqrt65)(-1) 1+8db... smaller db/dt = -1.133 m/s Boat approaching the dock at 1.133 m/s
3 Answers · Science & Mathematics · 17/04/2007
Boat speed = b. Stream current speed = c. since speed = distance /time, b+c = 48 miles/3 hours = 16, b- c... = 4. Subtracting the second from first eliminates ' b ' to leave 2c = 12. c = 6 miles / hour = Stream current
4 Answers · Science & Mathematics · 13/07/2011
...3 hr 18/(b-c) = 3 18 = 3b - 3c 2b + 2c = 3b - 3c 5c = b by substitution 18 = 2c + 2(5c) 18 = 12c c = 1.5 km/hr b = 5(1.5) = 7.5 km/hr Speed of boat in still water: 7.5 km/hr current: 1.5 km/hr
3 Answers · Science & Mathematics · 22/01/2010
b = speed of boat c = speed of river current distance / time = speed 24 miles / 2 hours = b + c 12 mph = b + c [1] 18 miles / 3 hours = b - c 6 mph = b - c [2] [1] - [2]: 6 mph = 2c c = 3 mph
3 Answers · Science & Mathematics · 21/12/2009
try this: http://local.yahoo.com/results?fr=dd-local-more&stx= boat +rental&csz=Conneaut% 2C +OH
2 Answers · Travel · 26/06/2007
...b = height of dock, and c = length of rope. a^2 + b^2 = c^2 2a da/dt + 2b db/dt = 2c dc/dt a da/dt + b db/ddt = c dc/dt 5 da/dt + 12(0) = 13 • 4 5 da/dt = 52 da/dt = 10.4 The boat is going 10.4 ft/sec. As it gets closer to...
1 Answers · Science & Mathematics · 11/10/2010
... some website links: http://www.ctshirts.co.uk/Blue% 2C -sky-and-white-stripe- boating -blazer?q=shopping||BL025BLU|||||||||||||&cm_mmc=CT%20Shirts...
1 Answers · Beauty & Style · 27/02/2011
use the pythagorean theorem - a^2 + b^2 = c^2 12^2 + 16^2 = c^2 144 + 256 = c^2 400 = c^2 20 = c differentiate: 2a(da/dt) + 2b(db/dt) = 2c (dc/dt) 2(12)(0) + 2(16)(db/dt) = 2(20)(15) 32db/dt = 600 db/dt = 18.75 ft/m
2 Answers · Science & Mathematics · 08/11/2011
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