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...of the boat to the dock C = length of rope that is pulling the boat Differentiating the above, 2A(dA/dt) + 2B(dB/dt) + 2C (dC/dt) Since A = 6 ft (constant), dA/dt =0 dB...

1 Answers · Science & Mathematics · 16/04/2008

...3 hr 18/(b-c) = 3 18 = 3b - 3c 2b + 2c = 3b - 3c 5c = b by substitution 18 = 2c + 2(5c) 18 = 12c c = 1.5 km/hr b = 5(1.5) = 7.5 km/hr Speed of boat in still water: 7.5 km/hr current: 1.5 km/hr

3 Answers · Science & Mathematics · 22/01/2010

b = speed of boat c = speed of river current distance / time = speed 24 miles / 2 hours = b + c 12 mph = b + c [1] 18 miles / 3 hours = b - c 6 mph = b - c [2] [1] - [2]: 6 mph = 2c c = 3 mph

3 Answers · Science & Mathematics · 21/12/2009

...b = height of dock, and c = length of rope. a^2 + b^2 = c^2 2a da/dt + 2b db/dt = 2c dc/dt a da/dt + b db/ddt = c dc/dt 5 da/dt + 12(0) = 13 • 4 5 da/dt = 52 da/dt = 10.4 The boat is going 10.4 ft/sec. As it gets closer to...

1 Answers · Science & Mathematics · 11/10/2010

...b = height of dock, and c = length of rope. a^2 + b^2 = c^2 2a da/dt + 2b db/dt = 2c dc/dt a da/dt + b db/ddt = c dc/dt 5 da/dt + 12(0) = 13 • 4 5 da/dt = 52 da/dt = 10.4 The boat is going 10.4 ft/sec. As it gets closer to...

3 Answers · Science & Mathematics · 02/03/2010

...know a^2 + b^2 = c^2 derivative: 2a*da/dt + 2b*db/dt = 2c *dc/dt (divide by2) (1)(0) +(8)db/dt = (sqrt65)(-1) 1+8db... smaller db/dt = -1.133 m/s Boat approaching the dock at 1.133 m/s

3 Answers · Science & Mathematics · 17/04/2007

...b + c) = 1 b + c = 8 b = 8 - c Speed of current—c: c + 6 = 8 - c 2c = 2 c = 1 Speed of boat : = 1 + 6 = 7 Answer: speed of current, 1 mph; speed of boat , 7 mph

3 Answers · Science & Mathematics · 29/09/2009

...at rightangles from A to B (the boat ). The line BC is the distance ... => (4-x) = BC*SinC = 4/Sin^ 2C T(C) =2*4/Sinc + 3*4 /Sin...

1 Answers · Science & Mathematics · 30/06/2011

...substitute x in 2. into x in 1. 1. x + c = 10m/h (6+c)+c=10 6+ 2c =10 c=(10-6)/2 c=2m/h Therefore, the speed of the current is 2miles/hr b) Now just consider the boat 's speed, without the current's speed: Plug in...

2 Answers · Science & Mathematics · 06/04/2011

Variables: r = rate of boat c = speed of current Convert 20 minutes to ... equation. 10 = (r - c) / 2 10 = (30 - c - c) / 2 10 = (30 - 2c ) / 2 Cross-multiply. 10 * 2 = (30 - 2c ) * 1 20 = 30 - 2c ...

3 Answers · Science & Mathematics · 30/01/2009

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