To find the

**area of**the**sector**, you have to know the angle**of**the**sector**. If the angle is in degrees the**area of**the**sector**would be :**A**= (T / 360) ( 72 ) cm sg............ T angle**of**the**sector**in degrees.1 Answers · Education & Reference · 27/12/2012

**area of sector**= (n/360)x (**area of circle**), where n = number**of**degrees From the given.... (72/360) x...positive value is accepted r = 5 ANSWER The**circle**has**a**radius**of**51 Answers · Education & Reference · 11/12/2009

This is how.... http://www.mathwords.com/

**a**/**area**_**sector**_**circle**.htm6 Answers · Education & Reference · 13/07/2007

Ans = D Well area of a circle is : π * r^2 So area of sector is (Angle / 360) * π * r^2 Therefore: ( (360-60) / 360 ) * 3.14 * 7^2 = 128.22 in²

1 Answers · Education & Reference · 30/03/2012

Area of Sector = ½ × (θ × π/180) × r^2 = ½ × (24 x π/180) x 8.4^2 = 14.78 cm^2

1 Answers · Education & Reference · 13/12/2012

Use these steps: 1) Find the area of circle . = π r² 2) Divide that by 2, to get the area of semicircle 3) divide that by 3, to get the area of each segment = π r²/6 =π 8*8/6 =10.6 π =33.52 square units/

1 Answers · Education & Reference · 14/11/2009

2r r*theta = 7 => theta = (7-2r)/r (1/2)r^2 * theta = 3 => (1/2)r (7-2r) = 3 => 2r^2-7r 6 = (2r-3)(r-2) = 0 r = 1.5 cm, 2 cm

2 Answers · Education & Reference · 27/02/2017

...3.14 * 9^2. This is 254.34. To find the

**sector area**, put the**sector area**x over the entire**area of**the**circle**, and set it equal to the degree**of**the angle out**of**360. So... x/254.34 = 120...4 Answers · Education & Reference · 17/06/2009

Call the fraction

**of**the**circle of**the**sector**f, then f pi r^2=80.9 and f 2 pi r =16 when you divide the first equation by the second, you get r/2 =5.05625 r=10.11 Answers · Education & Reference · 07/01/2014

A whole circle is 360º, so 60º is 1/6 of the circle . So 13.5pi is 1/6 of the total area . 6 * 13.5pi = 81pi ... arc length of the sector is going to be...

3 Answers · Education & Reference · 09/07/2010