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  1. To find the area of the sector , you have to know the angle of the sector . If the angle is in degrees the area of the sector would be : A = (T / 360) ( 72 ) cm sg............ T angle of the sector in degrees.

    1 Answers · Education & Reference · 27/12/2012

  2. area of sector = (n/360)x ( area of circle ), where n = number of degrees From the given.... (72/360) x...positive value is accepted r = 5 ANSWER The circle has a radius of 5

    1 Answers · Education & Reference · 11/12/2009

  3. This is how.... http://www.mathwords.com/ a / area _ sector _ circle .htm

    6 Answers · Education & Reference · 13/07/2007

  4. Ans = D Well area of a circle is : π * r^2 So area of sector is (Angle / 360) * π * r^2 Therefore: ( (360-60) / 360 ) * 3.14 * 7^2 = 128.22 in²

    1 Answers · Education & Reference · 30/03/2012

  5. Area of Sector = ½ × (θ × π/180) × r^2 = ½ × (24 x π/180) x 8.4^2 = 14.78 cm^2

    1 Answers · Education & Reference · 13/12/2012

  6. Use these steps: 1) Find the area of circle . = π r² 2) Divide that by 2, to get the area of semicircle 3) divide that by 3, to get the area of each segment = π r²/6 =π 8*8/6 =10.6 π =33.52 square units/

    1 Answers · Education & Reference · 14/11/2009

  7. 2r r*theta = 7 => theta = (7-2r)/r (1/2)r^2 * theta = 3 => (1/2)r (7-2r) = 3 => 2r^2-7r 6 = (2r-3)(r-2) = 0 r = 1.5 cm, 2 cm

    2 Answers · Education & Reference · 27/02/2017

  8. ...3.14 * 9^2. This is 254.34. To find the sector area , put the sector area x over the entire area of the circle , and set it equal to the degree of the angle out of 360. So... x/254.34 = 120...

    4 Answers · Education & Reference · 17/06/2009

  9. Call the fraction of the circle of the sector f, then f pi r^2=80.9 and f 2 pi r =16 when you divide the first equation by the second, you get r/2 =5.05625 r=10.1

    1 Answers · Education & Reference · 07/01/2014

  10. A whole circle is 360º, so 60º is 1/6 of the circle . So 13.5pi is 1/6 of the total area . 6 * 13.5pi = 81pi ... arc length of the sector is going to be...

    3 Answers · Education & Reference · 09/07/2010

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