( 40 / 360 ) x ( pi r^2 ) =

**area of a sector of**40 degrees An arc**of**length 4 pi is an arc that...3 Answers · Science & Mathematics · 12/02/2010

... length r= radius x=angle in radians For

**Area of A sector**:**A**=(1/2) (r^2) (x) where r= radius x=angle in radians...5 Answers · Science & Mathematics · 22/05/2010

... the

**area of a**full circle.**Area of**circle:**A**= Pi*r^2**Area of sector**: S =**A**/6 = (Pi/6)r^2 solve the last**equation**for r: r = sqrt(6S/Pi) put the value**of**14 in for S and do the...4 Answers · Science & Mathematics · 23/09/2015

The area of a sector is given by the equation A = ½r²θ, where θ is in radians. ...

2 Answers · Education & Reference · 30/01/2010

...½(5/2)(5/2) sin(2arcsin(3/4)) = 75√(7)/64 ≈ 3.10. The area of the sector is (the circle has radius 3) A _s = ½(3)² 2arcsin(3/4) ≈ 7.63. The area of the region...

1 Answers · Science & Mathematics · 14/01/2011

for the

**sector**. first find the**area of a**whole circle then work out what fraction the**sector**is . example**a**90 degree**sector**is 90/360 part**of a**whole circle . (1/4)**a**segment is like**a sector**minus**a**triangle1 Answers · Education & Reference · 23/03/2013

...2) For the area you want to compute 50/360 times the area of the circle. A ( of the defined part of the circle) = (50/360)*π*r^2 = (5/36)*π*(16)^2...

2 Answers · Science & Mathematics · 03/11/2008

1.

**equation**for**area of sector A**: (transpose so you have r on one side)**A**= (.5)r^2(theta) r = (15*(2))^(.5)/(.3...1 Answers · Science & Mathematics · 16/04/2009

take the internal angle to be t r+r+r(t)=100

**A**=0.5*r*r(t) from first**equation**you get r(t)=100-2r Substituting it into the second**equation**gives**A**=0.5*r*(100-2r) =50r-r*r1 Answers · Science & Mathematics · 28/09/2008

...360 degrees we can see that the this

**sector**is 90/360=1/4 the**area of a**circle with radius r as described by the above**equation**. Thus, the**area of**this**sector**(As) can be written as... As=1/4*pi*r^2 plugging...3 Answers · Science & Mathematics · 29/11/2012