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1. ### Area and Arc Math Question Help??

a ) 2*pi*15*(100/360) = (25/3)*pi =~ 26.179938779914943653855361527329 m b) pi*(20^2)*(65/360) = (650/9)*pi =~ 226.89280275926284500007979990352 m^2

1 Answers · Science & Mathematics · 20/06/2019

2. ### Math Circle problem ??

. Area of a sector is given as follows: A = ( θ/360° )πr² A = ( 130°/360°) * π * ( 7.2 )² A = 18.72π square units A = 58.81 square units ━━━━━━━━━━

4 Answers · Science & Mathematics · 16/06/2019

3. ### Find the area of the sector in a circle with radius of 6 cm and a central angle of 90°??

Area A = π r² ......radius r = 6 cm ...... A = π (6 cm)² ...... A ...

5 Answers · Science & Mathematics · 16/06/2019

4. ### The central angle of a sector of a circle with radius 20 cm is 65°. Determine the area of the sector ??

... imagine that the question asked for the area of the full circle. A = πr² A = π(20 cm)² A ...you don't want the full 360°, you just want a sector that is 65°, so multiply by the fraction: ...

4 Answers · Science & Mathematics · 15/06/2019

5. ### A sector of a circle has central angle 50 degrees and area 141.4 cm squared. What is the radius of the circle?

50° = 5π/18 radians 141.4 = (1/2)(5π/18)r^2 r = 18 cm

3 Answers · Science & Mathematics · 12/06/2019

6. ### Calculus problem?

... of circle perimeter = s + 2r = 1 meter s = 1 - 2r θ = s/r = (1-2r)/r radians A = area of sector  = [θ/(2π)]πr²  = θr²/2  = ((1-2r)/r)r²/2  = (1-2r...

1 Answers · Science & Mathematics · 07/12/2016

7. ### This math problem is very hard, if you can do it please try and show your work?

... like 60° + 60° = 120° (hard to read) = ⅔π radians Area of a sector AOB A = ½θr² r² = 2A/θ ...

2 Answers · Science & Mathematics · 29/11/2016

The smaller semicircle has a diameter of 1 cm, so an area of π/8 cm^2. The 60° sector overlapping the smaller semicircle has an area of .. 1/6*π...

1 Answers · Science & Mathematics · 27/11/2016