... of the entire circle is πr² = π·21² = 441π mi². A 60° sector represents 60°/360°, or 1/6 of the circle. Therefore, the area of the sector = 1/6 of 441π mi² = 147π/2 mi² ≈ 230.9 mi²...

2 Answers · Science & Mathematics · 27/02/2017

The

**area of a sector**of circle of radius R swept...the area of the whole circle whose area is πR². Notice...ratio gives the above formula A = πR²/(2π/Θ) = ...5 Answers · Science & Mathematics · 18/02/2012

**Sector**arc-length = 20 cm radius, r = 10 cm**Area of**the**sector**= pi(r^2)*20 / 2pi*r**Area**= 10*r = 10*10 = 100 sq.cm >==========< ANSWER1 Answers · Science & Mathematics · 03/08/2011

(45/360) * pi * 6^2 = 4.5pi cm^2

4 Answers · Science & Mathematics · 18/11/2012

... by two radii

**of a**circle and the arc the two radii subtend. The arc**of**the circle is equal in ... each r,the are**of sector**is simply**area of**entire circle times x/360...2 Answers · Science & Mathematics · 19/05/2011

i)

**Area of a sector**of a circle is given...the circle and θ is the angle of the sector in radians. ii) In...deg = π radians] So A = (1/2)(9)(2π/3) = 3π sq m2 Answers · Science & Mathematics · 06/11/2012

A hexagon is inscribed in a circle. => the side = r the area of hexagon = 6*(1/2 √3r/2 *r) = 3√3/2 r^2 => 6 equ. triangles the area ...

1 Answers · Science & Mathematics · 16/10/2015

...the circumference. If it is

**a sector**, then it is 2 X radius + length**of**the arc Radius = 8cm circumference...8 + 5.582 = 21.582 cm ANSWER**Area of**circle = 3.14 X 8 X 8...2 Answers · Science & Mathematics · 02/08/2012

... you the fraction

**of**the semicircle that the**sector**takes up. Then multiply by... pi*(radius^2), since that's the**area of**the whole semicircle. That is, half**of a**circle's**area**. The other option...1 Answers · Science & Mathematics · 27/02/2017

...82d, and 56.25d. We subtract the areas

**of**the three pie shaped sectors from the**area of**the triangle to get the answer.The**area**in the**A**circle is 16pi x(29.93/360) = 4.18 B is .82 and C ...1 Answers · Science & Mathematics · 27/09/2011