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As you get higher the air gets thinner, which means you need more speed to get lift. But since the air is thinner there is also decreasing oxygen, which means at some point the plane just plateaus because the air doesn't have...

4 Answers · Science & Mathematics · 25/08/2020

It depends how accurate you are trying to be. Let’s assume the model only has to deal with a horizontal flight-path. (Which is very inaccurate model.) The drag force (D) is approximately proportional to v². So D...

4 Answers · Science & Mathematics · 05/06/2020

Vp = velocity of plane = 110 m/s Vp(x) = x-component of plane's velocity = 110 m/s Vp(y) = y-component of plane's velocity = 0 m/s θp(com) = compass direction of plane = 90 ° θp(xy) = direction of plane on x-y axes = 0 ° Va = velocity of air = 41 m/s Va(x) = x-component of air's velocity = to be...

2 Answers · Science & Mathematics · 14/07/2020

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**airplane**whose velocity is measured in cm/s. Hmmmm must be a...1 Answers · Science & Mathematics · 06/08/2020

Well, if it ascends a distance of 12 km, then it is 12 km above the ground. But if traveled a distance of 12 km at an angle of 50º above the horizontal, then it ascended y = 12km * sin50º = 9.2 km and I'm pretty sure that's what you're...

1 Answers · Science & Mathematics · 02/06/2020

centripetal force CF = m*V^2/r = m*410^2/(3.6^2*2150) =6.033*m weight W = m*g =9.806*m banking angle from vertical = arctan(CF/W) = arctan (6.033/9.806) = 31.34°

3 Answers · Science & Mathematics · 05/02/2020

a) What is the force acting on the plane? a = acceleration = 2.0 m/s² m = mass = 120,000 kg F = force = to be determined F = ma F = (120,000 kg)(2.0 m/s²) F = 240,000 N = 240 kN b) What is the velocity of the plane...

2 Answers · Science & Mathematics · 27/09/2020

(B) mv^2/r = m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator. (A) v^2/r <= 6.45*g => r >= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2) = around 15m but use a calculator.

1 Answers · Science & Mathematics · 12/12/2019

Drag force F: F = ρa*V^2/2*C*A being : C the drag coeff (0.5 for a sphere) A the cross-section area PI*r^2 in m^2 ρa the density of air equal to 1.25 kg/m^3 V the speed in m/sec weight force WF = 4/3*PI*r^3*ρb*g (ρb is the...

3 Answers · Science & Mathematics · 29/11/2019

... back in the 1960's for use in propelling interstellar spacecraft, not airplanes . It addresses a very basic problem of how a spacecraft could ever carry...

3 Answers · Science & Mathematics · 09/06/2020

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