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Assume that the plane has velocity v₀ at the origin s = v₀t + ½at² 477.20 = v₀6.00 + ½a6.00² 477.20 - 18a = v₀6.00 79.533 - 3a = v₀ also 630.90 = v₀7.00 + ½a7.00² 630.90...

2 Answers · Science & Mathematics · 04/09/2019

I agree with your value for centripetal acceleration, but the implication here is that the plane is not following a circular path. Try calculating the acceleration in the original direction of travel as the component of velocity in that direction changes from 217.1 m/s to zero...

2 Answers · Science & Mathematics · 12/09/2019

625km/h * 1m/s / 3.6km/h = 173.6 m/s horizontal (radial, or centripetal) acceleration ax = v²/r vertical acceleration is zero, which means that ay = g where ax and ay are provided by the "lift." ax / ay = tanΘ = v² / gr r = v² / gtanΘ = (173.6m/s)²...

1 Answers · Science & Mathematics · 04/10/2019

centripetal force CF = m*V^2/r = m*410^2/(3.6^2*2150) =6.033*m weight W = m*g =9.806*m banking angle from vertical = arctan(CF/W) = arctan (6.033/9.806) = 31.34°

3 Answers · Science & Mathematics · 05/02/2020

(B) mv^2/r = m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator. (A) v^2/r <= 6.45*g => r >= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2) = around 15m but use a calculator.

1 Answers · Science & Mathematics · 12/12/2019

Drag force F: F = ρa*V^2/2*C*A being : C the drag coeff (0.5 for a sphere) A the cross-section area PI*r^2 in m^2 ρa the density of air equal to 1.25 kg/m^3 V the speed in m/sec weight force WF = 4/3*PI*r^3*ρb*g (ρb is the...

3 Answers · Science & Mathematics · 29/11/2019

The first step is to convert the final speed of the

**airplane**from km/h to m/s. One kilometer is 1,000 meters. One...2 Answers · Science & Mathematics · 04/09/2019

During the time the ball is falling, it has a vertical acceleration of 9.8 m/s^2. Use the following equation to calculate the time. d = vi * t + ½ * a * t^2 Since ball is moving horizontally, its initial vertical velocity...

3 Answers · Science & Mathematics · 13/09/2019

... assuming no drag find Vx Vx = Vo cos 30 = 252(0.8660) = 218.24 m/s find Vyi Vyi = 252 sin30 = 126 m/s find Vyf after fall Vyf^2 = Vyi^2 + 2 g d = 126^2 + 2(-9.81)(-2100) = 57078 Vfy = -238.91 m/s (we choos negative root because it's...

2 Answers · Science & Mathematics · 20/09/2019

Depends on what you take as the density of air. Δp = ½ρ(V² - v²) For ρ = 1.25 kg/m³, I get Δp = 7500 Pa If you find this helpful, please select Favorite Answer!

1 Answers · Science & Mathematics · 20/05/2020

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