...final vertex connected to the:origin is of the form : Z=(d,e,h). {For a right prism we would require...zero. Since, for the maximum volume, ½( ach )≠0, one can quickly deduce the values for b, d, and e...

2 Answers · Science & Mathematics · 28/01/2013

...h+ki) = (ac-bd)h - (ad+bc)k + [(ac-bd)k + (ad+bc)h]i = ach - bdh - adk + bck + (ack - bdk + adh + bch)i = a(ch-dk) - b(ck...v ≠ 0, this means n = 0, so 1/v is of the form m = m+0i. but vm = 1, so m must be 1/v. since v is...

2 Answers · Science & Mathematics · 14/10/2011

...2) = (ac+2bd)g + 2(ad+bc)h + [(ac+2bd)h + (ad+bc)g]√2 = acg + 2bdg + 2adh + 2bch + ( ach + 2bdh + adg + bcg)√2 = a(cg+2dh) + 2b(ch+dg) + [a(ch+dg) + b(cg+2bh)]√2 = (a + b...

2 Answers · Science & Mathematics · 04/10/2011

...r) = (n - r - 1)! Sometimes you have to write these out in longer

**form**to realise that they work.1 Answers · Science & Mathematics · 29/03/2011

..., x^2 + 2y^2 = T/5 I simplified it to this

**form**because each answer is divisible by 5. Now substitute each answer for ...1 Answers · Science & Mathematics · 05/10/2010

...refuse to serve together? On similar lines we get the no of ways to

**form**committee of 4 men and 3 women where 2 particular women don...1 Answers · Science & Mathematics · 04/02/2010

... MR as a one letter n others as remain => (MR)

**ACH**this can be arranged in 4! ways{ considering MR...4 Answers · Science & Mathematics · 24/06/2009

...there are no exponents, and it is in the

**form**of f(x) = mx + b, where m is he slope (3) and b ....html To evaluate the functions for**ach**value, simply replace x with that value. For example, for the...1 Answers · Science & Mathematics · 23/03/2009

... have <BCA = <

**ACH**(same angle) <CAB = < ...altitude to hypotenuse equal to the product of the segments it formed on the hypotenuse1 Answers · Science & Mathematics · 03/03/2009

...take every pair of the same number and take it out. You take one from

**ach**pair and multiply them and put them in front of the radical. ...8 Answers · Science & Mathematics · 27/04/2008