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  1. ... initial potential energy of the bowling ball at the top of the tower is: PE = mgh = (70 N )(15 m) (note: you are ...39;s the weight of the ball) = 1050 J . At the ground, all...

    2 Answers · Science & Mathematics · 27/12/2011

  2. ...2mgh simplified: 0.7mv^2 = mgh 0.7 x (63.5/9.8) x 5.5^2 = 137.2 J 137.2 J = work done by force work done = force x distance 137...

    2 Answers · Science & Mathematics · 20/03/2011

  3. We know work done = force*displacement = 80*10 J = 800 J When lifted 0.5 m,work done = 80*0.5 = 40 J

    3 Answers · Science & Mathematics · 19/05/2013

  4. ...so all the energy is gravitational potential energy. mgh = 1620 J h = 1620 / 7 / 9.8 h = 23.6m But you released...continue 23.6 - 2 = 21.6m Above your head... a bowling ball! RUN!

    6 Answers · Science & Mathematics · 23/09/2008

  5. a . The ball comes off the recoil at the same speed. Since it was moving in the positive... the change in momentum is p(final) - p(initial) = -7kg*m/s - 7kg*m/s = -14kg*m/s c. Impulse ( J ) is defined by two equations: Impulse = change in momentum = Force * Time...

    3 Answers · Science & Mathematics · 25/12/2009

  6. 1 Joule = 1 Newton * meter 35 J = x N * 0.5m (35 Nm / 0.5m) = xN 75 N = xN x = 75N mass = 75N / 9.8N mass = 7.7kg

    2 Answers · Science & Mathematics · 11/09/2008

  7. ...p1 = m*v1 Final momentum of bowling ball: p2 = m*v2 Impulse-momentum theorem: J = p2 - p1 J = m*(v2 - v1...v2 - v1)/deltat You will get a negative number, reverse the v'...

    2 Answers · Science & Mathematics · 11/07/2011

  8. bowling ball: Ek = ½mv² = ½•7.41kg•(2.56m/s)² = 24.3 J ping-pong: Ek = 24.3 J = ½•0.00221kg•v² v...

    2 Answers · Science & Mathematics · 06/01/2011

  9. ... F = m* a *(1+k) where k for a solid sphere = 0.40 F = 4*2*1.4 = 11.2 N ...............Answer X = ... = F*X = 11.2*1 = 11.2 J ............Answer for both parts...

    1 Answers · Science & Mathematics · 14/12/2012

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