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  1. That would be... 1.4 * 10^(5) * -9.9 → -1.386 * 10^6 Good luck!

    1 Answers · Science & Mathematics · 13/02/2012

  2. Think right triangle, use Pythagorean Theorem to solve: distance = √(4² + 5²) distance = √41 = 6.4 km .

    1 Answers · Science & Mathematics · 20/04/2009

  3. The triangle shape are it's appear at second quatrain of the coordinate system ,which AB at 63 degree it's shorter line than the AC at 38 degree and BC line .This make the AC hypotenuse of the triangle ,using C^2=A^2+B^2...

    1 Answers · Science & Mathematics · 28/02/2014

  4. cos(31.5) = y/42 y = 42cos(31.5) y = 35.81 mi sin(31.5)= z/42 z = 42sin(31.5) z = 21.94 mi 63^2 = Z^2 + (x + y)^2 63^2 = 21.94^2 + (x + 35.81)^2 3969 = 481.36 + x^2 + 71.62x + 35.81^2 3969 = 481.36 + x^2 + 71.62x + 1282.36 x^2 + 71.62x = 2205.28 x^2 + 71.62x + 1282.36 = 3487.64 (x + 35.81)^2 = 3487.64 x + 35.81 = +- 59.06 x = 23.25 or -94.87 distance can't be...

    1 Answers · Science & Mathematics · 18/04/2015

  5. ...the coast oriented north-south: water east; land westpoint A on the shore closest to the boat...value of 1.68 hours (2 dp) when x = 1 ➞ Point P should be located 1 mile south of...

    2 Answers · Science & Mathematics · 07/12/2011

  6. You can use the law of cosines to get the distance. ......___________________ c =√ a^2 + b^2 - 2abcos(y) ......_______________________________ c =√ 2^2 + 4^2 - 2(2)(4)(cos 135 degrees) ......__________________ c =√ 4 + 16 - 16( - .7071) ......____________ c =√ 20 + 11.3137 ........_______ c = √ 31.3137 c = approx. 5...

    2 Answers · Science & Mathematics · 14/11/2009

  7. 64 * 4 = 264 48 * 4 = 192 distance² = 264² + 192² <=> distance² = 106560 <=> distance = sqr (106560) = 326.43 miles

    3 Answers · Science & Mathematics · 31/03/2009

  8. B is 5 east of A and 1 South of A so displacement is Square root( 5^2 + 1^2)

    1 Answers · Science & Mathematics · 31/10/2011

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