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  1. ... is the hypotenuse. using Pathagorus, you can determine that point B is 20/√2 = 14.14 miles west and 20/√2 = 14.14 miles south of point A.

    1 Answers · Science & Mathematics · 26/12/2017

  2. Angle opposite to side 4.25 = 180 - [(70+25)+(35+20)] = 30° Required side/sin55 = 4.25/sin30 Required side = 4.25 (sin55/sin30) = 6.96 mile

    3 Answers · Science & Mathematics · 06/12/2017

  3. ...road to Well 1, then share a pipeline from Well 1 cross-country to a point 1.02 km west of the intersection and down the road the remaining distance to the Tanks...

    2 Answers · Science & Mathematics · 03/12/2017

  4. ...2/2 mi/h = √2 mi/h Hence broken down into its east and west components the speed vector relative to water is √2i + √2j mi/h...

    2 Answers · Science & Mathematics · 05/11/2017

  5. ... using the tangent function. Let x represent the distance that the target point T is north of the line AB. Then the east-west distance from A or B to the north-south line through T will be x...

    2 Answers · Science & Mathematics · 25/10/2017

  6. ... the time lapsed from first meet to the second meet point = 1 + 1/2 = 3/2 hr. So the time taken by cyclist = First meet...

    2 Answers · Science & Mathematics · 27/10/2017

  7. In ΔATC : tan32°30' = TC/AC AC = TC/tan32°30' …… [1] In ΔBTC : tan19°22' = TC/BC BC = TC/tan19°22' …… [2] In ΔABC, by Pythagoras' theorem...

    1 Answers · Science & Mathematics · 23/10/2017

  8. Try doing this using the methods I've shown you in some of the questions I've already answered for you, and get back to me if you still can't. The basic line of approach is: add information to the system and follow where...

    1 Answers · Science & Mathematics · 22/10/2017

  9. The length of AD: tan 22° = 250 / AD AD = 250/tan 22° The length of BD: tan 12° = 250/BD BD = 250/tan 12° The length of AB: AB² = AD² + BD² - 2(AD)(BD) cos 45° AB² = (250/tan 22°) + (250...

    3 Answers · Science & Mathematics · 15/10/2017

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