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By R = √[W^2 + N^2] =>R = √[(10)^2 + (25)^2] =>R = 26.9 N/C =>c

2 Answers · Science & Mathematics · 12/12/2012

by tanθ = 10/25 = 0.4 = tan21.8* =>θ = 21.8* W of N =>b. 68.2* N of W

2 Answers · Science & Mathematics · 17/12/2012

...2.02 N and

**points**due east If Electric field**points**due**west**Then F**points**due east 3rd year physics...2 Answers · Science & Mathematics · 12/04/2010

a. its 69

**west**and 69 south, so its a 45-45-90 triangle. The magnitude is 69 sqrt... direction is then 45 degrees south of**west**. b. Go**west**but then go north, as it is minus B. still a 45-45-90 triangle. 69 sqrt...1 Answers · Science & Mathematics · 24/05/2011

Let Force act on

**point**O (origin) F = 20 N {**west**} displacement (s) = 70.7 m south-**west**** the angle between Force and displacement...1 Answers · Science & Mathematics · 23/06/2007

...represent your distance of 23 km. south. Now draw another line going

**west**from that**point**and make it 14 units long to represent the leg going 14 km.**west**. ...2 Answers · Science & Mathematics · 11/02/2013

A= 69

**West**B= 69 South 69^2 + 69^2 = x^2 x= 97.6 A+B= 69 W and 69 S = 97.6 SW A-B= 69 W and 69 N = 97.6 NW2 Answers · Science & Mathematics · 01/09/2009

...km = 2.5 km south of his starting

**point**and 5 . cos 30 = 4.3 km**west**of his starting**point**.1 Answers · Science & Mathematics · 01/03/2010

...cos(25)i + sin(25)j) = B*cos(25)i + B*sin(25)j C is

**pointed**10 deg**West**of South, or 260 deg on a X-Y plane C = C*(cos...1 Answers · Science & Mathematics · 22/05/2015

**west**total 160km + 35km*cos45º = 185 km south total 35km*sin45º = 25 km d = √(185² + 25²) km = 186 km Θ = arctan(25/185) = 7.6º S of**West**If you find this helpful, please award Best Answer!1 Answers · Science & Mathematics · 12/10/2017

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