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**v**- 7) = 7/([**v**+ 1][**v**- 7]) - 5([**v**+ 1][**v**- 7]) - 4(**v**+ 1) = 7 - 5(v² - 7v +**v**- 7) - 4v - 4 = 7 - 5(v² - 6v - 7) - 4v = 11...3 Answers · Science & Mathematics · 14/09/2011

{

**v**_1,...,**v**_n} is a spanning set of**V**. And**v**is a vector of**V**. There exist n numbers...2 Answers · Science & Mathematics · 11/03/2009

ok, suppose

**V**,W are subspaces of some larger space U. we... non-empty. why? because the 0-vector (at the very least) is in both**V**and W. 2) suppose x1,x2 are in**V**∩W. we need to show...3 Answers · Science & Mathematics · 06/07/2011

**v**dx + (2x + 1 - vx) dv = 0 vdx/dv + (2−**v**)x = −1 dx/dv + (2/**v**−1)x = −1/**v**… (i) IF is exp( ∫(2...2 Answers · Science & Mathematics · 04/09/2012

...the problem the quadrants in which 'u' and '

**v**' lies. Since 'sin(u)' is positive...combination that 'u' is in first and '**v**' is in second. ==> Sin(u -**v**...1 Answers · Science & Mathematics · 05/02/2013

Do you mean the following: h = f / [(1 +

**v**/s)] Then solve by first making denominators equal...latter term can now be multiplied by f. h = f * [s/(s +**v**)] h = fs/(s +**v**) Now start trying to separate the term which contains**v**. ...1 Answers · Science & Mathematics · 16/11/2008

... is the subspace generated by the set {u,

**v**,w}. If the set {u,**v**,w} is linearly independent... is no way U is not a subset of**V**, by definition. Lobosito - He said**V**...3 Answers · Science & Mathematics · 01/01/2009

**v**^3+12v^2+36v Factor out the common factor:**v**(**v**^2+12v+36) Factor the remaining quadratic:**v**(**v**+ 6)^22 Answers · Science & Mathematics · 06/02/2011

t = (u +

**v**) /**v****v*** t = ( (u +**v**) /**v**) ***v****v*** t = u +**v****v*** t -**v**= u +**v**-**v****v*** t -**v**= u**v*** ( t - 1 ) = u**v*** ( t - 1 ) / ( t - 1) = u / (t - 1)**v**= u / ( t - 1)4 Answers · Science & Mathematics · 05/10/2010

...width * base * height. Since it's a cube, they're all equal. So

**V**= x^3 Surface area on the other hand, is going to be the sum...1 Answers · Science & Mathematics · 27/02/2009