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  1. 20m = (v_o_sin35°)(159m/v_o_) - (4.90 m/s)(159m/v_o_) 20 = 159*sin35° - 4.9*159/v_o_ 4.9*159/v_o_ = 159*sin35° - 20 multiply v_o_ on both sides: 4.9*159 = (159*sin35° - 20)*v_o_ divide 159*sin35° - 20 on both sides: v_o_ = 4.9*159/(159*sin35° - 20)

    1 Answers · Science & Mathematics · 29/02/2008

  2. E = 1/2 m v^2 divide both sides by 1/2 m 2E/m = v^2 swap sides...and m are both positive, so you can take the square root of both sides: v = √(2E/m) Then plug in your numbers: v = √(2...

    3 Answers · Science & Mathematics · 15/11/2011

  3. V= V0 sin 2 π f t, where V=26V at t= 6.5 ms V= 26sin (2 π 60* 6.5e-3) = 16.57 V (Note that the angles...

    2 Answers · Science & Mathematics · 29/11/2011

  4. 1) v = u + at u = 0 at time t so ignore it. v = at t = v / a t = v / (4 - v^2) 2) x = ut + 1/2at^2 (u =0...sqrt(2)t - vt sqrt(x) = (sqrt(2) - v)t sqrt(x) / t = sqrt(2) - v sqrt(2) - (sqrt(x) / t) = v I think.. Just make sure...

    1 Answers · Science & Mathematics · 20/06/2008

  5. |Z| = |V|/|I| |V| = 3 |I| = 39.439√2 Here is where there...

    1 Answers · Science & Mathematics · 24/05/2013

  6. V(=1500)=kQ/r ------- (1) E(=10^5)=kQ/r^2--------(2) (1)÷(2) V/E=r therefore r=1500/10^5=1.5*10^(-2)m=1.5cm the electric potential at distance...

    1 Answers · Science & Mathematics · 05/10/2011

  7. V = I x R 115 = 6.5 x R (rearranging the equation) R = V/I = 115/6.5 = 17.6923 Ohms (to 4 decimal places) ...

    2 Answers · Science & Mathematics · 07/03/2007

  8. ...a projection of the length of A onto the direction of the unit vector B. V is a vector, and can be written as a linear combination of 3 ...

    1 Answers · Science & Mathematics · 16/12/2007

  9. a. q = C x V We have V given that V=18V...5788x10^-10)x18 = 6.441984x10^-9 C b. W = 0.5 x q x V or W = 0.5xCxV^2 or W = q^2 / 2C...

    1 Answers · Science & Mathematics · 04/10/2011

  10. ... for the stone to climb from height A to height B we use the formula V/2=V-g*t which means V=2*g*t (where g is the gravitational...

    2 Answers · Science & Mathematics · 13/02/2010

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