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...: mv^2 / 2 + umgs cos(a) = mgs sin(a)

**v**^2 = 2gs(sin(a) -**u**cos(a))**v**= sqrt[ 2 * 9.81 * 60 (sin(30) - 0.09 cos(30)) ] = 22.3 m/**s**. (b) mv^2 / 2 = umgs**s**=**v**^2 / (2ug) = 281 m.2 Answers · Science & Mathematics · 12/07/2008

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...2a and plug it into

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...and the distance is the average velocity times time, that is to say

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Using your convention .. ↓ is -ve v = u + gt -49.10 = 0 + (-9.80 x t) t = 49.10 / 9.80 .. .. ►t = 5.0 s (assuming 'final velocity' doesn't mean terminal velocity)

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stopping force F = m (

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