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If

**u**and v are linearly independent, then whenever c1**u**+ c2 v = 0 (a zero vector), then c1 = c2 = 0 (as scalars). Also note that span(**u**, v) for example equals the set of all {c1**u**+ c2 v} where c1 and c2 range over...1 Answers · Science & Mathematics · 22/03/2012

**u**cant know 100%.. well, to know for sure, ask him directly. but to try to be sure abt his feelings, try the following:**u**knw he likes**u**back if: -he txts**u**bak wenever**u**txt him..thus...7 Answers · Family & Relationships · 22/12/2006

[1] What color hair do

**u**have? Dark brown. (: [2] What color eyes do**u**have? Once...15 pull-ups/chin-ups? Yessir. [6] What kinda pizza do**u**like? You know ;] the good stuff. [7] Are**u**outgoing? Sometimes...40 Answers · Entertainment & Music · 07/08/2009

sec [ arctan(

**u**) + arccos(v)] let arctan(**u**) = A tan A =**u**==> opposite side =**u**and adjacent side = 1, hypotenuse = √(**u**^2 + 1) sin A =**u**/ √(**u**^2 + 1) ------(1) and cos A = 1 / √(**u**^2 + 1...1 Answers · Science & Mathematics · 27/07/2010

I'll let P(

**u**) denote the projection of**u**along V and O(**u**) =**u**- P(**u**). ...let be the dot product. We want to show, for all w in V, that (O(**u**),w) = (**u**-P(**u**),w) = ((**u**-v),w) = 0. Well, how do we find v? v ...1 Answers · Science & Mathematics · 23/01/2009

Since dim

**U**= 1, we have that**U**= span{**u**} for some**u**in**U**. Likewise, dim... otherwise. Then, there exists a nonzero vector v in**U**∩ W. So, v = au for some nonzero scalar a and v = bv + cw for some ...1 Answers · Science & Mathematics · 02/02/2015

(

**u**/5) + (**u**/10) - (**u**/6) = 1 First thing I would do is multiply everything by 30 to get rid of all the fractions 6u + 3u - 5u = 30 9u - 5u = 30 4u = 30**u**=30/4=7.5 _/1 Answers · Education & Reference · 24/08/2008

**u**x v=(u2v3-u3v2)i+(u3v1-u1v3)j+(u1v2-u2v1)k**u**x v=(2*0-3*1)i+(3*0-3*0)j+(-3*1-2*0) =(-3,0,-3) To show that**u**...1 Answers · Science & Mathematics · 18/03/2012

||

**u**|| = √((**u**_1)² + (**u**_2)² + (**u**_3)²) where**u**= (**u**_1,**u**_2,**u**_3) = (2, -2, 3...3)² + (4)²) ||v|| = √(1 + 9 + 16) ||v|| = √(26) ||**u**|| + ||v|| = √(17) + √(26) ||**u**+ v|| = √((**u**+v_1)² + (**u**+v_2...1 Answers · Science & Mathematics · 27/05/2009

**u**- 2/3 = - 4/3**u**- 3/5 Multiply everything by 15(the GCM of 3 and 5) you get 15u -10= -20u -9 15u+20u= -9 +10 35u=1**u**=1/353 Answers · Science & Mathematics · 08/03/2012