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yes

**u**can, its called self infliction. they also have a name for "cutters" but i cant think of it.**u**will know if**u**have a problem if**u**cut urself to release any pain that**u**are...5 Answers · Health · 15/07/2007

Let

**u**=x-2. Then, x=**u**+2 and dx = du Then, \int 5x/(x-2)^(1/2) dx becomes \int 5(**u**+2) ***u**^(-1/2) du= 5\int (**u**^(1/2)+2**u**^(-1/2)) du= 5 (2/3**u**^(3/2)+ 4**u**^(1...3 Answers · Science & Mathematics · 02/08/2006

wow

**u**dont no how to play pool? well first**u**try to hit a ball in and if its a stiped ball**u**have to only hit the ...4 Answers · Games & Recreation · 09/05/2008

**U**feel on your face the chilling sensation of the snow that melts.**U**---ndoubtedly there is no rock on earth that melts.**U**----...21 Answers · Entertainment & Music · 01/12/2006

(du/dx)+

**u**+au^(5/4)+**u**^4 = 0 so (du/dx) = -(**u**+au^(5/4)+**u**^4) and thus -du/(**u**+au^(5/4)+**u**^4) = dx so we reach the... x(**u**) to get the desired functional form**u**(x) Unfortunately, I'm not certain if...2 Answers · Science & Mathematics · 19/05/2008

a^

**u**= a^**u**e^**u**/e^**u**a = e^ln(a) a^**u**= [e^ln(a)]^**u**a^**u**= e^[ln(a)***u**] ∫a^**u**d**u**= ∫e^[**u**ln(a)] d**u**Let v =**u**ln(a) --> dv = ln(a) d**u**∫a^**u**d**u**= [1/ln(a)]∫e^v dv ∫a^**u**d**u**= [1/ln(a)] e^v + C ∫a^**u**d**u**= [1/ln...2 Answers · Science & Mathematics · 09/12/2008

**u**= 1 + x^(1/3)**u**- 1 = x^(1/3) (**u**- 1)^3 = x d/du (**u**- 1)^3 = dx/du 3(**u**- 1)^2 = dx/du dx = 3(**u**- 1)^2 du integrate 1 / (1 + x^(1/3)) dx = integrate (1 /**u**) * (3)(**u**- 1)^2...1 Answers · Education & Reference · 01/12/2013

No

**u**can't lose weight without eating it actually makes**u**sick and tired and**u**have to eat just lest better like stop going to Mickey d'...6 Answers · Health · 11/02/2013

**u**just feel like**u**REALLY wanna do it...but DONT do it if**u**KNOW**u**dont wanna...that could lead to bad pressure. wait**u**r talking about sex, right?2 Answers · Family & Relationships · 08/07/2007

**u**^2 = -2u + 15**u**^2 + 2u - 15 = 0**u**^2 + 5u - 3u - 15 = 0**u**(**u**+ 5) - 3(**u**+ 5) = 0 (**u**- 3)(**u**+ 5) = 0**u**- 3 = 0 or**u**+ 5 = 0**u**= 3 or**u**= -5 If**u**= 3 we have: 3 = sqrt(-2*3 + 15) 3 = sqrt(-6 + 15) 3 = sqrt(9) TRUE If**u**= -5...4 Answers · Science & Mathematics · 10/06/2016

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