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  1. u =2x+1 du=2dx plugging in 0 and 2 into the u equation to find the new limits of integration u (0) = 1 u (2) = 5 answer is .5 ∫[1,5] u ^.5 du so number 3

    1 Answers · Science & Mathematics · 05/04/2008

  2. (du/dx)+ u +au^(5/4)+ u ^4 = 0 so (du/dx) = -( u +au^(5/4)+ u ^4) and thus -du/( u +au^(5/4)+ u ^4) = dx so we reach the... x( u ) to get the desired functional form u (x) Unfortunately, I'm not certain if...

    2 Answers · Science & Mathematics · 19/05/2008

  3. Let U = A vector = <Ux, Uy, Uz> Let... = A/|A| Let V = The vector projection of U on A is = ( U •A)Â U •A = (...

    1 Answers · Science & Mathematics · 14/03/2014

  4. ∫ [x /(10 - √x)] dx = let (10 - √x) = u → √x = 10 - u → square both sides: x = (10 - u )² → dx = 2...3(10)u² - u³] / u } du = distribute and break it into: - 2 ∫ (1000/ u ) du + 2 ∫ [(300u)/ u ] du - 2 ∫ [(30u²)/ u ] du + 2 ∫ (u³/ u ) du = pull...

    1 Answers · Science & Mathematics · 17/02/2009

  5. By definition u .v x w = |v x w| | u | cosθ where θ is the angle between u and v x w... where Θ is the angle between v and w. So u .v x w = |v||w| sinΘ | u | cosθ and this is equal to | u ||v...

    2 Answers · Science & Mathematics · 03/10/2009

  6. U -substitution in an algebra class is only representative of simplification. For instance, you can change a part of the equation that has 4xy^2 into U , and simplify the problem using U , and then plug the 4xy^2 into the equation...

    4 Answers · Science & Mathematics · 31/07/2006

  7. I'll let P( u ) denote the projection of u along V and O( u ) = u - P( u ). ...let be the dot product. We want to show, for all w in V, that (O( u ),w) = ( u -P( u ),w) = (( u -v),w) = 0. Well, how do we find v? v ...

    1 Answers · Science & Mathematics · 23/01/2009

  8. u du/(16 + u ^2) Let w = 16 + u ^2 then dw = 2u du so (1/2) dw = u du We now have (1/2) ∫ dw/w = (1/2) ln w = (1/2) ln (16 + u ^2) + C

    3 Answers · Science & Mathematics · 09/04/2011

  9. ∫( u + 2)^2 * ( u + 1)^(1/2) du from -1 to 0 Let z = u + 1 => dz = du ∫(z + 1)^2 * z^(1/2) dz from 0 to 1 (Note the ...

    3 Answers · Science & Mathematics · 04/12/2013

  10. 4u OVER u ^2 PLUS u OVER u -1 = 4u/ u ^2 + u /( u - 1) = 4/ u + u /( u - 1) = [4( u - 1) + 4u]/[ u ( u - 1)] = (8u - 4)/[ u ( u - 1)] = [4(2u - 1)]/[ u ( u - 1)] C over C^2 + 9c +20 MINUS...

    1 Answers · Science & Mathematics · 25/10/2013

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