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  1. ... x is in V and T is onto then we can find u in U such that T(u)=x. Applying S on both sides...

    2 Answers · Science & Mathematics · 31/10/2012

  2. u = y + xy v = y - xy Add u + v: u + v = 2y y = (u + v) / 2 Subtract u - v: u - v = y + xy - (y - xy) u - v = xy + xy u - v = 2xy x = (u - v) / 2y x = (u - v) / (u + v) Answer: x = (u - v) / (u + v) y = (u + v) / 2

    3 Answers · Science & Mathematics · 24/11/2015

  3. u and v are parallel u.v = |u||v| u x v = 0 (Cross product) Note they do not necessarily lie on the same plane or line, all we can say is that they have the same direction.

    4 Answers · Science & Mathematics · 29/06/2010

  4. ...of sine and cosine. [More explicitly, the rational function is R(u, v) = v/(u + uv). So, R(sin x, cos x) = cos x/(sin x + sin x cos x...

    1 Answers · Science & Mathematics · 01/04/2012

  5. Hello, ∫ [x /(2x + 1)] dx = let: 2x + 1 = u 2x = u - 1 x = (1/2)(u - 1) dx = (1/2) du then, substituting...u) du = (1/4)u - (1/4) ln | u | + C let's substitute back 2x + 1 for u: (1/4)(2x + 1) - (1/4) ln |2x + 1| + C = (1/2)x + (1/2) - (1/4) ln |2x...

    1 Answers · Science & Mathematics · 01/03/2013

  6. ...attempt submitted whilst non compos mentis (a) If u=(u1,u2,u3,u4) ∈ U┴ then u is perp to both spanning... to u2=1/11, u4=8/11 ∴ p−w belongs to U

    1 Answers · Science & Mathematics · 11/04/2012

  7. ...3u|^2 + |v|^2 - 2|3u||v|cosθ, where θ is the angle between 3u (and, thus, u) and v. Since |3u| = 3|u|, we have: |3u + v|^2 = (3|u|)^2 + |v|^2 - 2(3...

    2 Answers · Science & Mathematics · 12/09/2012

  8. Let X = {a_n: n ≥ 1} U {a}. Suppose x ∈ R^k \ X. Then x ≠ a and x...

    2 Answers · Science & Mathematics · 28/11/2013

  9. Consider the linear transformation F : U → (U + W)/W given by F...v in U : v is in W} .........= U ∩ W. The result now follows from...

    2 Answers · Science & Mathematics · 17/03/2012

  10. ln u = ln (2vx²) ln u = ln (2v) + ln (x²) ln u = ln (2v) + 2 ⋅ ln (x) If you allow for a little substitution: y = 2⋅x + ln...

    3 Answers · Science & Mathematics · 19/10/2007

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