...the relative velocity of approach = relative velocity of separation, or 472 m/s = V -

**U**where V is the post-collision velocity of the nucleus and**U**is...1 Answers · Science & Mathematics · 18/06/2020

Energy stored E = 1/2 CV^2 where V = voltage b

**u**t C = Q/V so V = Q/C & V^2 = Q^2/C^2 s0 E = 1/2 CV^2 = 1/2 C*Q^2/C^2 = Q^2/(2C) Now if...2 Answers · Science & Mathematics · 17/06/2020

Left turn or Right turn?

3 Answers · Science & Mathematics · 27/07/2020

Please remember to select a Best Answer from among your results.

1 Answers · Science & Mathematics · 02/08/2020

(a)

**U**= mgh = 330kg * 9.81m/s² * 300m = 9.71e5 J (b) friction work W...0.12 * 330kg * 9.81m/s² * 500m * (4/5) = 9.32e4 J (c) KE =**U**- W = 8.78e5 J (d) 8.78e5 J = ½ * 330kg * V²...1 Answers · Science & Mathematics · 10/07/2020

**U**= (kQ₁Q₂/r₁₂) + (kQ₂Q₃/r₂₃) + (kQ₁Q₃... = –3 C r₁₂ = 10 m r₂₃ = 4 m r₁₃ = 6 m**U**= k(35•16/10 – 16•3/4 – 35•3/6) You can do the math, ...1 Answers · Science & Mathematics · 14/06/2020

... to write that as T then yo

**u**get T*dv/dt = T*a(t) =**u**- v(t) --> a(t) = acceleration So T is some sort of time constant...1 Answers · Science & Mathematics · 11/09/2020

(1/

**u**) + (1/v) = 1/f (1/78.3) + (1/v) = -1/45.9 1/v = -(1/45.9) - (1/78.3) v = 1 / [-(1...78.3)] Image distance, v = -28.9 cm Height of the image = 4.56 × |v/**u**| = 4.56 × |-28.9/78.3| = 1.68 cm Since v is negative, the image ...3 Answers · Science & Mathematics · 24/07/2020

1) energy stored in spring was

**U**= ½kx² = ½ * 4784N...8.4 m/s (8.43 before rounding) 5) Now**U**= ½ * 4784N/m * (0.14m)²...1 Answers · Science & Mathematics · 07/08/2020

good start --

**U**= kQq / d at point of triangle,**U**= 2*kQq / x at midpoint of base,**U**= 2*kQq / (x/2) = 4*kQq / x so Δ**U**= 2*kQq / x2 Answers · Science & Mathematics · 05/02/2020