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  1. ...http://www.mai.liu.se/~pehac/kurser/TATM54/booktot.pdf http://www.maths.tcd.ie/~dwilkins/Courses/311/311NumTh.pdf http://www.mathe2.uni...

    2 Answers · Science & Mathematics · 25/11/2010

  2. We can actually write out all of the elements of θ. Since θ is a homomorphism, multiplication by n in Z6 corresponds to nth power in S3. θ([0]) = θ(0 * [1]) = (1 2 3)^0 = (1) θ([1]) = (1 2 3) θ([2]) = θ(2 * [1]) = (1 2 3)^2 = (1 3 2) θ([3]) = θ(3 * [1]) = (1 2 3)^3 = (1) θ...

    1 Answers · Science & Mathematics · 02/04/2012

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