Yahoo Web Search

  1. Sort by

  1. (23.4 cm^3) x (101.325 kPa / 109 kPa) x (273 K) / (67 + 273) K = 17.5 cm^3

    1 Answers · Science & Mathematics · 05/06/2019

  2. (1.1 L) / (22.4 L/mol) x (44.01 g CO2/mol) = 2.2 g CO2 V = nRT / P = (3.59 mol) x (0.082057338 L atm/K mol) x (214 K) / (0.900 atm) = 70.0 L P = nRT / V = (0.156 mol) x (0.082057338 L atm/K mol) x (24.7...

    1 Answers · Science & Mathematics · 31/05/2019

  3. ... is clear, if this is a gas, that you did not start at STP since the original volume is not 22.4 L.

    2 Answers · Science & Mathematics · 02/10/2019

  4. ... / T2 ............. P2, V2 and T2 are at STP P2 = P1V1T2 / (T1P2) V2 = 726 torr x 15.5 mL...

    2 Answers · Science & Mathematics · 30/05/2019

  5. Molar volume of a gas at STP = 22.4 L/mol No. of moles of the gas = (3.00 L) / (22...

    2 Answers · Science & Mathematics · 24/07/2019

  6. ... = 6.23 mol we must assume some T and P If it is STP then V = 6.23 mol * 22.4 l/mol = 139.5 L round appropriately When...

    3 Answers · Science & Mathematics · 24/05/2019

  7. 4) (80.0 mL) x (-12.5 + 273.15) K / (273.15 K) x ((1 atm x 101.325 kPa/atm) / (109 kPa)) = 71.0 mL 5) (1.65 atm) x (4.54 L / 5.33 L) x (103 + 273) K / (75.0 + 273) K = 1.52 atm 6) (915 mL) x (1170 mm Hg / 842 mm Hg) x (-23 + 273) K...

    2 Answers · Science & Mathematics · 24/05/2019

  8. 4 Fe + 3 O2 → 2 Fe2O3 (49.7 g Fe) / (55.8450 g Fe/mol) x (3 mol O2 / 4 mol Fe) x (22.414 L/mol) = 15.0 L O2

    1 Answers · Science & Mathematics · 20/05/2019

  9. Supposing the reaction to be: NH4NO3 → N2O + 2 H2O (0.165 L N2O) / (22.414 L/mol) x (1 mol NH4NO3 / 1 mol N2O) x (80.0434 g NH4NO3/mol) = 0.589 g NH4NO3

    1 Answers · Science & Mathematics · 20/05/2019

  10. (0.0455 mol) x (22.414 L/mol) = 1.02 L

    1 Answers · Science & Mathematics · 20/05/2019

  1. Try asking your question on Yahoo Answers