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  1. We have STP , and we know that 1 mole of gas occupies V = 22.4 L = 0.0224... / m = 0.0224m³/mol / 0.0166kg/mol spec vol = 1.35 m³/kg at STP Hope this helps!

    1 Answers · Science & Mathematics · 28/06/2020

  2. ... by W = -nRT*ln(Vf / Vi) One mole at STP means Vi = 22.4 L so -1000 J = -1mol * 8.314J...

    1 Answers · Science & Mathematics · 18/06/2020

  3. 2 H2O2 → 2 H2O + O2 (30 g H2O2) / (34.01468 g H2O2/mol) x (1 mol O2 / 2 mol H2O) x (22.414 L/mol) = 9.88 L So answer c.

    1 Answers · Science & Mathematics · 08/06/2020

  4. ...one day option. While cyclists are welcome to participate in the STP ride without any preparation or training, few do.  First, the ride ...

    2 Answers · Travel · 01/06/2020

  5. ...ideal gas law .. (2) what does S and T and P stand for in STP .. (3) is it easier to write STP or T = 273.15K...

    1 Answers · Science & Mathematics · 28/05/2020

  6. 1 mole = 22.4 liters 22.4 liters × .005 = .112 liters = 112 cm³ ³√112 = 4.82 cm edge length.

    1 Answers · Science & Mathematics · 28/05/2020

  7. 72.1 L O2 / 22.4 L/mol = 3.22 mol O2 108 g Fe / 55.845 g/mol = 1.93 mol Fe 1.93 mol Fe X (3 mol O2/4 mol Fe) = 1.45 mol O2 to react completely with available Fe. So, Fe is the limiting reactant 1.93 mol...

    3 Answers · Science & Mathematics · 26/05/2020

  8. Exact question: https://answers.yahoo.com/question/index?qid=20200522022256AA4g9c5

    3 Answers · Science & Mathematics · 22/05/2020

  9. P₁V₁/T₁ = P₂V₂/T₂ (150 kPa x  1 atm / 101.325 kPa))(6.85 L) / (35.0°C + 273.15)K = (1 atm)V₂/(273.15 k) V₂ = (150 kPa x 1 atm / 101.325 kPa)(6.85 L)(273.15 k)/[(1 atm)(35.0°C + 273.15)K...

    1 Answers · Science & Mathematics · 28/05/2020

  10. ...mole H2/ 2 mole Al) x 0.0815 = 0.122 mol 1 mole of any ideal gas at STP occupies 22.4 L so H2 occupies 22.4 x 0.122 = 2...

    2 Answers · Science & Mathematics · 21/04/2020

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