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  1. At STP 1 mole of any ideal gas occupies a volume of 22.4 L mass of 1 mole of C2H2 = (2 x 12.01) + (2 x 1.008) = 26.036 g So at STP 26.036 g of C2H2 has a volume of 22.4 L density = mass / volume...

    2 Answers · Education & Reference · 17/06/2012

  2. ...write the balanced equation: O2 + 2H2 → 2H2O at STP 1 mol of O2 occupies 22.4 L so mol O2 available = 5...

    1 Answers · Education & Reference · 17/06/2013

  3. ...= 1 atm V= unknown n= 2.082 R= .0821 T = 273.15 K (STP means 1atm and 273.15 K) V=(2.082)(.0821)(273.15)/(1) this...

    1 Answers · Education & Reference · 18/11/2012

  4. correct the volume to STP at STP, one mole of gas occupies 22.4 L 22.4 L / (corrected volumes) = (molar mass) / 5.00 g

    1 Answers · Education & Reference · 26/02/2013

  5. ummm such an easy question and no answers, lol

    1 Answers · Education & Reference · 21/01/2010

  6. CaCO3 = CaO + CO2 moles CO2 = 67.0 L/22.4 L/mol=2.99 moles CaCO3 = 2.99 mass CaCO3 = 2.99 mol x 100 g/mol= 299 g

    1 Answers · Education & Reference · 12/10/2010

  7. 1. convert 0.2625 moles to grams using its molecular mass and dimensional analysis. then divide it by its density to get the volume occupied. 2. use ideal gas law. to get the number of moles of the gas. then divide it to 1.643 g.

    1 Answers · Education & Reference · 23/10/2010

  8. The response you are looking for is here http://study-exams.com/product/bus-330-final-paper-principles-of-marketing/?a=3

    1 Answers · Education & Reference · 08/10/2014

  9. 4NH3 + 3O2 -----> 2N2 + 6H2O 3 L of oxygen is required to produce 2 L of nitrogen. ∴ 0.10 x 3/2 = 0.15 litres of O2 required.

    1 Answers · Education & Reference · 15/04/2011

  10. Google, wikipedia.

    1 Answers · Education & Reference · 25/02/2013

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