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I believe a mol will occupy 22.4 liters at

**STP**. So, take 88.5 and divide it by the molar mass of methane to find out how many...1 Answers · Science & Mathematics · 23/12/2012

2.20 Moles * 22.4 L/mole= 49.28 L (49.3 if you are using sig-figs.) There are always 22.4 L/mole @

**STP**.6 Answers · Science & Mathematics · 20/03/2008

... 3 * 0.41 = 1.23 mol of O2. Finally, since 1 mol of any gas at

**STP**occupies 22.41L, the required volume of O2 is...2 Answers · Science & Mathematics · 05/04/2010

...that molar volume is the volume occupied by one mole of ideal gas at

**STP**, the volume of that ideal gas is historically known to be ~22.414 L...2 Answers · Science & Mathematics · 17/01/2008

Since 1 mol of any gas occupies 22.41 L at

**STP**, we have: Moles Cl₂ = 8.29/22.41 = 0.37 mol. We can...1 Answers · Science & Mathematics · 08/06/2010

1 mol occupies 22.4 litres at

**STP**(standard temperature and pressure). Therefore 3 mols would occupy three...1 Answers · Science & Mathematics · 12/09/2010

...to compute its new volume because now the volume is the only unknown because

**STP**means standard temperature and pressure. Now the fact is that each...1 Answers · Science & Mathematics · 16/10/2010

2.99 X 10^23 molecules of chlorine 2.99 X 10^23 molecules (1 mole Cl2/6.02 x10^23 molecules)= .496678 moles Cl2 .496678 moles (22.4L at

**STP**/mole)=11.13 L1 Answers · Science & Mathematics · 14/04/2010

Each mole of gas at

**STP**occupies 22.4 L. 889.4ml = 0.8894L moles CH4=0.8894L/22.4Lper mole = ?1 Answers · Science & Mathematics · 20/08/2012

... (add 273) (750*40)/295= (760*x)/273 x = 36.53 L by the way,

**STP**(standard temperature and pressure) is 273 K / 0 C and 1 atm / 760 atm...1 Answers · Science & Mathematics · 18/06/2008

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