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  1. I believe a mol will occupy 22.4 liters at STP . So, take 88.5 and divide it by the molar mass of methane to find out how many...

    1 Answers · Science & Mathematics · 23/12/2012

  2. 2.20 Moles * 22.4 L/mole= 49.28 L (49.3 if you are using sig-figs.) There are always 22.4 L/mole @ STP .

    6 Answers · Science & Mathematics · 20/03/2008

  3. ... 3 * 0.41 = 1.23 mol of O2. Finally, since 1 mol of any gas at STP occupies 22.41L, the required volume of O2 is...

    2 Answers · Science & Mathematics · 05/04/2010

  4. ...that molar volume is the volume occupied by one mole of ideal gas at STP , the volume of that ideal gas is historically known to be ~22.414 L...

    2 Answers · Science & Mathematics · 17/01/2008

  5. Since 1 mol of any gas occupies 22.41 L at STP , we have: Moles Cl₂ = 8.29/22.41 = 0.37 mol. We can...

    1 Answers · Science & Mathematics · 08/06/2010

  6. 1 mol occupies 22.4 litres at STP (standard temperature and pressure). Therefore 3 mols would occupy three...

    1 Answers · Science & Mathematics · 12/09/2010

  7. ...to compute its new volume because now the volume is the only unknown because STP means standard temperature and pressure. Now the fact is that each...

    1 Answers · Science & Mathematics · 16/10/2010

  8. 2.99 X 10^23 molecules of chlorine 2.99 X 10^23 molecules (1 mole Cl2/6.02 x10^23 molecules)= .496678 moles Cl2 .496678 moles (22.4L at STP /mole)=11.13 L

    1 Answers · Science & Mathematics · 14/04/2010

  9. Each mole of gas at STP occupies 22.4 L. 889.4ml = 0.8894L moles CH4=0.8894L/22.4Lper mole = ?

    1 Answers · Science & Mathematics · 20/08/2012

  10. ... (add 273) (750*40)/295= (760*x)/273 x = 36.53 L by the way, STP (standard temperature and pressure) is 273 K / 0 C and 1 atm / 760 atm...

    1 Answers · Science & Mathematics · 18/06/2008

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