... The ideal gas law says that one mole of an ideal gas at

**STP**occupies 22.4 liters. Therefore, treating N2...1 Answers · Science & Mathematics · 21/06/2013

Use the fact that 1 mol of any gas occupies 22.41L at

**STP**. 8) We see that 5.62L of N₂(g) corresponds to...1 Answers · Science & Mathematics · 25/04/2010

What exactly constitutes

**STP**is not exactly black and white, but density of oxygen is 1.429 g/L at 0°C, 101.325 kPa ♣♦1 Answers · Science & Mathematics · 31/01/2011

...39+35.5+16*3=39+35.5+48=122.5g 1 mole occupies 22.4 litres at

**STP**, thus 122.5g of KClO3 occupies 22.4 liters. 12.25 gm of...2 Answers · Science & Mathematics · 14/03/2013

.... *Be aware of the unit for P, V, and R. At

**STP**, P = 1.00 atm, T = 0oC = 273.15K molar mass of NH3...2 Answers · Science & Mathematics · 05/03/2014

volume of one mol of any gas at

**stp**is 22.4L 1 mol of CO2: 12g carbon + 2*(16gm oxygen)= 44g ...1 Answers · Science & Mathematics · 25/01/2014

... = n R T P V/T = n R = constant for

**STP**(standard temperature pressure) condition, P = 1 atm = 1.01 E5 Pa, ...2 Answers · Science & Mathematics · 25/12/2008

...mol = 6.02 × 10^23 molecules One mol = 22.4L of gas at

**STP**2.09 × 10^22 * ( 1 mol / ( 6.02 * 10^23 ) ) = 0.035 mol 0.035mol * ( 22.4L / 1...3 Answers · Science & Mathematics · 19/08/2013

... of carbon dioxide are contained in 550 mL of this gas at

**STP**1 mole of any gas at**STP**has a volume of 22.4 liters...2 Answers · Science & Mathematics · 15/02/2013

1 mol of any gas at

**STP**(assuming ideal conditions, of course) occupies 22.41L. So all you need to do is multiply each amount by 22.41L to the corresponding volume.5 Answers · Science & Mathematics · 05/06/2010