One mole of an ideal gas will occupy a volume of 22.4 liters at

**STP**1 L=1 dm^3 22.4 L=22.4 dm^3 0.335/22.4≈0.01496 0.01496*6.022*10^23≈9.006*10^21 molecules1 Answers · Education & Reference · 08/01/2015

We know that one mole of any gas occupies 22.4 L at

**STP**. Therefore: (100 L) / (22.4 L/mole) = 4.46 moles of...1 Answers · Education & Reference · 22/09/2008

...... a mole of all gasses has a volume of 22.4L at

**STP**... you only have 1.0L, so that's 1/22.4 mol of the gas... from that, you...1 Answers · Education & Reference · 19/12/2009

densty = molar mass x p / RT at

**STP**: p = 1 atm and T = 273 K molar mass CO2 = 44 g/mol= density = 44 x 1 atm / 0.0821 x 273 = 1.96 g/L2 Answers · Education & Reference · 05/01/2009

...0581 moles of propane 1 mole is contained in 24 dm^3 at

**STP**Therefore 0.0581 moles is contained in 0.0581...1 Answers · Education & Reference · 13/02/2013

(25.2 g Cl) x (1 mole Cl / 35.5 g Cl) x (22.4 L Cl / 1 mole Cl) = 15.9 L Cl (

**STP**)1 Answers · Education & Reference · 18/12/2012

1 mole of any gas occupies 22.4 L of volume at

**stp**44.8/22.4 = 2 moles of O2 answer is c. 2.001 Answers · Education & Reference · 28/05/2011

41.5 ml x 1 L / 1000mL x 22.4 grams / 1 L = 0.00093 grams H2

**STP**'s conversion factor is 22.4 grams per liter1 Answers · Education & Reference · 30/04/2012

molar mass/molar volume = mass/volume = density @

**stp**, v=22.4L/mol molar mass = density(molar volume) = 4.7g/L (22.4L/mol) = 110g/mol1 Answers · Education & Reference · 09/01/2013

The volume that one mole of any gas occupies at

**STP**is 22.4 L. The calculation is simply: (26.6 moles) (22.4 L/mole) = 595.8 L.1 Answers · Education & Reference · 21/03/2012