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  1. One mole of an ideal gas will occupy a volume of 22.4 liters at STP 1 L=1 dm^3 22.4 L=22.4 dm^3 0.335/22.4≈0.01496 0.01496*6.022*10^23≈9.006*10^21 molecules

    1 Answers · Education & Reference · 08/01/2015

  2. We know that one mole of any gas occupies 22.4 L at STP . Therefore: (100 L) / (22.4 L/mole) = 4.46 moles of...

    1 Answers · Education & Reference · 22/09/2008

  3. ...... a mole of all gasses has a volume of 22.4L at STP ... you only have 1.0L, so that's 1/22.4 mol of the gas... from that, you...

    1 Answers · Education & Reference · 19/12/2009

  4. densty = molar mass x p / RT at STP : p = 1 atm and T = 273 K molar mass CO2 = 44 g/mol= density = 44 x 1 atm / 0.0821 x 273 = 1.96 g/L

    2 Answers · Education & Reference · 05/01/2009

  5. ...0581 moles of propane 1 mole is contained in 24 dm^3 at STP Therefore 0.0581 moles is contained in 0.0581...

    1 Answers · Education & Reference · 13/02/2013

  6. (25.2 g Cl) x (1 mole Cl / 35.5 g Cl) x (22.4 L Cl / 1 mole Cl) = 15.9 L Cl ( STP )

    1 Answers · Education & Reference · 18/12/2012

  7. 1 mole of any gas occupies 22.4 L of volume at stp 44.8/22.4 = 2 moles of O2 answer is c. 2.00

    1 Answers · Education & Reference · 28/05/2011

  8. 41.5 ml x 1 L / 1000mL x 22.4 grams / 1 L = 0.00093 grams H2 STP 's conversion factor is 22.4 grams per liter

    1 Answers · Education & Reference · 30/04/2012

  9. molar mass/molar volume = mass/volume = density @ stp , v=22.4L/mol molar mass = density(molar volume) = 4.7g/L (22.4L/mol) = 110g/mol

    1 Answers · Education & Reference · 09/01/2013

  10. The volume that one mole of any gas occupies at STP is 22.4 L. The calculation is simply: (26.6 moles) (22.4 L/mole) = 595.8 L.

    1 Answers · Education & Reference · 21/03/2012

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