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  1. at STP, 1mole of any gas occupies 22.4L 2H2 + O2 --> 2H2O 55g / 32g/mole = 1.72moles O2 1.72moles O2 x (2H2O / 1 O2) x 22.4L/mole = 77L

    2 Answers · Science & Mathematics · 19/06/2013

  2. ... of N2 = 0.714 mol Volume = moles * molar volume at stp Volume = 0.714 * 22.4 Volume = 15.99 L BTW ...

    2 Answers · Science & Mathematics · 20/03/2013

  3. 1 mole. of O2 = 32g. 1 mole. at STP occupies 22.4L. Density = Mass / Volume. Density of O2 at STP = 32g / 22.4L = 1.43g/L = 1.43kg/m³ have a blast!!!

    1 Answers · Science & Mathematics · 06/09/2009

  4. At STP 1 mole of any gas occupies 22.4 liter 1 mole F2 is 2 x 19 = 38 gram so 35 gram is (35/38) = 0.92 mole the volume is 0.92 x 22.4 = 20.6 liter

    1 Answers · Science & Mathematics · 30/12/2013

  5. In STP, ideal gas has 22.4 mol/1L. 5.6 L * 22.4 mol/1 L = 125.44 mols O2 With sig fig, 1.3 x 10^2 mols O2

    1 Answers · Science & Mathematics · 28/06/2010

  6. At STP a mole of any gas occupies 22.4 L. So 500L/22.4L/m =22.32m, however 500 has only 1 sig fig so 20 moles is the correct answer

    1 Answers · Science & Mathematics · 31/01/2012

  7. V1 = 39L @ stp, T1 = 273K P1 = 1atm P2 = 4atm T2 = 25oC...

    1 Answers · Science & Mathematics · 17/08/2013

  8. ...volume = # of moles * Ryberg's constant * Temperature. STP is standard temperature and pressure. So P = 1 atm, and T...

    1 Answers · Science & Mathematics · 28/03/2014

  9. ... ===> remember the molar gas volume (the volume of 1 mole of any gas at STP = 22.4-dm³) a.) 1.45-g FeO x ( 1 mol FeO / 71.8-g ...

    2 Answers · Science & Mathematics · 08/11/2013

  10. d = molar mass x p/RT at STP : p = 1 atm and T = 273.16 K d = molar mass x 1 / 0.08206 x 273.16 if you have the molar mass you can get d

    2 Answers · Science & Mathematics · 06/09/2009

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