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  1. Supposing the reaction goes to completion: a) (15.008 L H2) / (22.414 L/mol) × (6 mol HF / 3 mol H2) = 1.3392 mol HF b) (3.50 g N2) / (28.01344 g N2/mol) × (2 mol NF3 / 1 mol N2) × (22.414 L/mol) = 5.60 L NF3...

    1 Answers · Science & Mathematics · 19/06/2019

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