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1. ### Chemistry: If a pressure cooker has a safety valve that vents steam when the pressure exceeds 3.4 atm, what is the maximum temperature?

If "3.4 atm" is a gauge pressure (which is commonly used with pressure cookers) the temperature will be about 147.6°C. If "3.4 atm" is an absolute pressure the temperature will be about 138.2°C.

2 Answers · Science & Mathematics · 29/06/2017

2. ### PHYSICS FINAL QUESTION PLSS HELP. I NEED TO KNOW THE STEPS?

q = mC∆T 1.125x10^4J = 500 g x C x 50 deg C = 1.125x10^4J/500 g/50 deg C = 0.45 J/g/deg It could be iron if the value for iron was 0.45 J/g/deg instead of the indicated 450, although the indicated values...

3 Answers · Science & Mathematics · 16/06/2017

b. Before water can change state hydrogen bonds between water molecules must be broken.

2 Answers · Science & Mathematics · 13/06/2017

1. d The number of each atom need to be the same before and after the arrow. 2. b The energy all goes into breaking bonds when water boils and melts comment for explanation

2 Answers · Science & Mathematics · 13/06/2017

5. ### 30.0 L of hydrogen reacts completely to form steam. What volume of oxygen will be required in this reaction at STP. 2H2 + O2 = 2H2O?

Supposing the H2 was also measured at STP: (30.0 L H2) x (1 mol O2 / 2 mol H2) = 15.0 L O2

1 Answers · Science & Mathematics · 23/05/2017

6. ### How much heat (in kJ) is required to warm 13.0 g of ice?

...) x (13.0 g) x (109.0 - 100) ∘C = 235.17 J to heat the steam to 109.0 ∘C 380.38 J + 4336.8 J + 5439.2 J + 29341...

1 Answers · Science & Mathematics · 21/05/2017

7. ### How much heat is released when 105 g of steam at 100.0°C is cooled to ice at -15.0°C?

...mol) x (5.8284 mol) = 237.041 kJ = 237041 J from condensing the steam (75.4 J/(mol • °C)) x (5.8284 mol) x (100 - 0)°C = 43946 ...

2 Answers · Science & Mathematics · 14/05/2017

8. ### The enthalpy change for converting 1.00 mol of ice at -50.0°C to water at 70.0°C is ______?

1 mol H2O = 18.01532 g (2.09 J/gK) x (18.01532 g) x (0 - (-50.0)) K = 1882.6 J to warm the ice to its melting point (6.01 kJ/mol) x (1 mol) = 6.01 kJ = 6010 J to melt the ice (4.18 J/gK) x (18.01532 g) x (70 - 0) K = 5271.3 J to...

1 Answers · Science & Mathematics · 14/05/2017

9. ### Chemistry Problem Involving Heat Changes in Phase and Temp?

Follow the steps in this video https://www.youtube.com/watch?v=jy0CoTpi88Q You don't have the calculation for heating the ice up to melting since the ice is already at 0C. Just replace the numbers in the example with...

1 Answers · Science & Mathematics · 13/05/2017

10. ### How much heat in kj is released when 1.73 moles of steam at 154.5 celsius is cooled down to -15.0 celsius.(answer would be in kj 3 sig-figs)?

...x (1.73 mol) x (154.5 - 100.0)°C = 3397.1 J from cooling the steam to its boiling point (40660 J/mol) x (1.73 mol) = 70341.8 ...

1 Answers · Science & Mathematics · 11/05/2017