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  1. The Cp of steam is 2.01 J/g°C. How much energy is needed to heat 52.0 grams of steam from 100.0°C to 120.0°C?

    (2.01 J/g°C) x (52.0 g) x (120.0 - 100.0)°C = 2090 J

    1 Answers · Science & Mathematics · 03/03/2021

  2. What is the heat required to boil 743 grams of water in a kettle at 100c?

    ... 2.06 kJ/kgC = 2.06 J/gCspecific heat of steam is 2.1 kJ/kgK = 2.1 J/gKheat of fusion of...

    2 Answers · Science & Mathematics · 02/02/2021

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