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1. ### At 1 atm, how much energy is required to heat 87.0 g of H2O(s) at –10.0 °C to H2O(g) at 131.0 °C? Helpful constants can be found here.?

...g·°C)) x (87.0 g) x (131.0 - 100.0)°C = 5394 J to heat the steam to 131.0 °C 1815.69 J + 29023.2 J + 36400.8 J + 196359...

1 Answers · Science & Mathematics · 06/03/2019

2. ### ;-; pls help me?

...9 kJ Energy required to change 40.0 g of liquid water to steam at 100.0°C = m Lv = (40.0 g) × (2260 J/g) = 90400 J...

1 Answers · Science & Mathematics · 25/02/2019

3. ### Is steam a gas?

Live steam - greater than 100oC (or just ordinary humidity) is a gas. The "steam" you see coming from boiling water is a heterogeneous mixture of air, water vapor and liquid water.

6 Answers · Science & Mathematics · 20/02/2019

4. ### Why isn t zinc soluble in water?

...temperature some more. Zinc metal will react noticeably with high pressure, really hot steam. Zn(s) + H2O(g) --> ZnO(s) + H2(g)

5 Answers · Science & Mathematics · 12/02/2019

5. ### At 1 atm, how much energy is required to heat 57.0 g of H2O(s) at –12.0 °C to H2O(g) at 163.0 °C?

...g·°C)) x (57.0 g) x (163.0 - 100.0)°C = 7182 J to heat the steam to 163.0°C 1427.508 J + 19015.2 J + 23848.8 J + 128649...

1 Answers · Science & Mathematics · 01/02/2019

6. ### Equilibrium partial pressures question?

[NO]^2[H2]^2 /[N2][H2O]^2 = 1.54 x 10^-3 Pressure due to H2 and H2O = 1.87atm -0.168 – 0.225 = 1.477 atm Let y = pressure due to H2 Then 1.477 – y = pressure due to H2O (0.225)^2(y)^2 / 0.168(1.48-y)^2 = 0.00154 0.0506y^2 / 0.168( 2.18 -2...

1 Answers · Science & Mathematics · 30/01/2019