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  1. dv/dt => a = 6 - 2t so, v(t) = 6t - t² + v(0) Hence, v(t) = 6t - t² The maximum velocity occurs when a = 0 so, 6 - 2t = 0 i.e. when t = 3 Then, v(3) = 18 - 9 => 9 ms⁻¹ After 4 seconds we have: v(4) = 24 - 16 => 8 ms⁻¹ ds/dt...

    1 Answers · Science & Mathematics · 28/05/2020

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