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1. ### A 3.0 kg block slides along a horizontal surface with a coefficient of friction µk = 0.30. The block has a spe?

Your picture did not open. I am trying to answer your questions as far as possible with the help of your word problem only. 1) Use energy conservation here. Net change in kinetic energy = 0.5 mv^2 [as final speed = 0] = 4.86 J This...

1 Answers · Science & Mathematics · 19/01/2014

2. ### How much work must you do to push a 10 block of steel across a steel table at a steady spe?

that... doesn't seem to be a valid question. First, there's no units, so it's impossible to answer it for that reason alone. Second, if you want units of work, what you need is force and distance, not speed. W = FD And power is Work per unit time so...

1 Answers · Science & Mathematics · 15/01/2009

3. ### The viscous force on an oil drop is measured to be 6.0 10-13 N when the drop is falling through air with a spe?

You need to use terminal velocity ideas. Check this link: http://en.wikipedia.org/wiki/Stokes%27_law Hope this helps. your_guide123@yahoo.com

1 Answers · Science & Mathematics · 18/11/2012

4. ### The greatest force a level road can exert on the tires of a certain 2000kg car is 4 kn what is the highest spe?

Acceleration = (f/m) = 4,000/2,000) = 2m/sec^2. Maximum V = sqrt.(ar) = 20m/sec. (20 x 3.6) = 72kph., should you need that.

1 Answers · Science & Mathematics · 02/02/2014

5. ### A 69-kg fisherman in a 133-kg boat throws a package of mass m = 15 kg horizontally toward the right with a spe?

m1 v1 + m2 v2 = m1 u1 + m2 u2 m1 = 69 + 133 = 202 kg m2 = 15 kg v1 = v2 = 0 u2 - u1 = 4.4 m/s u2 = u1 + 4.4 m1 v1 + m2 v2 = m1 u1 + m2 u2 0 = 202 u1 + 15 (u1 + 4.4) 0 = 202 u1+ 15 u1 + 66 -66 = 217 u1 u1 = -66/217 = -0.304 m/s (it negative because the direction is opposed the package direction)

1 Answers · Science & Mathematics · 14/03/2013

6. ### A 6.0-kg block is pushed 8.0 m up a rough 37º inclined plane by a horizontal force of 75 N. If the initial spe?

a) 0.5*m*v^2 = 12 J b) F*d = 600 J c) F*d = -200J d) F*d = m*g*(8sin(37)) = -283.38 J e) F*d = 0 J f) W_net = 600 - 200 - 283.38 = 116.62 J

1 Answers · Science & Mathematics · 29/11/2009

7. ### A car traveling east at 45.6 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his spe?

When you driving at 45,6 m/s and you reduces your speed uniformly to 25.0 m/s you drive on the average 35.3 m/s In 4.20 s that is 148.26 m. So can also use the formal equations: a = (v1 - v0) / t. = (45.6 - 35.3)/4.2 and s = v0.t + (1/2).a.t^2 with s (at t=0) = 0...

1 Answers · Science & Mathematics · 06/10/2010

8. ### (a) What is the momentum of a garbage truck that is 1.20×104 kg and is moving at 10.0 m/s ? (b) At what spe?

(a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

1 Answers · Science & Mathematics · 14/10/2013

9. ### A croquet mallet delivers an impulse of 9.87 N s to a 0.54- kg croquet ball initially at rest. What is the spe?

By I = ∆P = m∆v =>9.87 = 0.54 x ∆v =>∆v = 18.28 m/s

1 Answers · Science & Mathematics · 21/10/2013

10. ### A 46.5 kg sled and person are moving along a level section of snow elevated at a height of 5.0 meters. The spe?

ENERGY AT THE TOP = ENERGY AT THE BOTTOM, FIND THE SPEED AT THE BOTTOM 1/2*m*v1^2 + m*g*h1 = 1/2*m*v2^2 + m*g*h2 In this case, set h2 = 0. All the m's cancel 1/2*v1^2 + g*h1...

1 Answers · Science & Mathematics · 09/12/2012