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  1. KE gets converted to Q, thermal energy KE = 1/2*m*v^2 Q = KE, assuming complete conversion to thermal energy. Thus Q = 1/2*m*v^2 Data: m:=1050 kg; v:=250/9 meters/sec; Result: Q = 405093...

    2 Answers · Science & Mathematics · 16/01/2010

  2. Angular speed is in radians, so divide the linear speed by the radius. (3.7) / (15) = 0.247, in whatever units you're using.

    2 Answers · Science & Mathematics · 07/06/2010

  3. the x component of Vi = 18.7@31.0 deg is 16.03 m/s so t = d / Vx = 29.0 / 16.03 = 1.329 s and the initial y component is 9.631 m/s so using the time from above Vyf = Vyi + g t = 9.631 + (-9.81)(1.329) = -3.4065 m/s combining the final x and y components (16.03...

    2 Answers · Science & Mathematics · 01/02/2011

  4. first calculate the time it took for sound to travel 45m v = d/t so t = d/v t = 45/330 t = .13636 secs subtract this time from the total time t = 1.45989 - .13636 t = 1.32353 secs last, using the remaining time, find the average velocity of the thrown ball v = d/t v = 45/1.32353 v = 34 m...

    3 Answers · Science & Mathematics · 22/12/2012

  5. a) The work done by the horizontal force = F*d*cos(theta) Here: F = 80 N, d = 4.8 m (displacement), theta = 39 degree (angle between the force and the direction of motion). Therefore W = (80)(4.8)(cos39) = 298 J b) To find the final kinetic energy we will find the...

    2 Answers · Science & Mathematics · 01/11/2012

  6. v^2=u^2 + 2as (3rd equation of motion) where v=final velocity (0); u = initial velocity; a=acceleration (-10 m/s^2) and s=distance (320m). So u^2 = 2as = 2 x 320 x 10 = 6400. This gives u = 80 m/s

    3 Answers · Science & Mathematics · 12/09/2006

  7. For a solid sphere, I = (2/5)mr² and rotational KE = ½Iω² = ½ * (2/5)mr² * (v/r)² = (1/5)mv² So: translational KE = ½ * 7.1kg * (4.6m/s)² = 75 J rotational KE = (1/5...

    2 Answers · Science & Mathematics · 09/11/2013

  8. we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

    2 Answers · Science & Mathematics · 02/05/2017

  9. From your problem statement it sounds like you're only interested in the vertical dimension, and you also need to neglect the effect of aerodynamic drag. With these assumptions, right before the ball hits the ground it has converted...

    2 Answers · Science & Mathematics · 15/07/2012

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