Let S denote the length of the shadow. When he's F feet from the pole, you have 6/15 = x/(F+x), where x = S - F 2(F+x) = 15x 2F = 13x, so S = F + (2F/13) = 28F/13 dF/dt = 4 ft/s dS/dF = 28...

2 Answers · Science & Mathematics · 06/04/2013

Let S denote the length of the shadow. When he's F feet from the pole, you have 6/15 = x/(F+x), where x = S - F 2(F+x) = 15x 2F = 13x, so S = F + (2F/13) = 28F/13 dF/dt = 4 ft/s dS/dF = 28...

2 Answers · Science & Mathematics · 06/04/2013

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