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1. ### How much will the spring be compressed when the block momentarily comes to a rest?

.... For a spring compression of "x," initial KE + GPE = SPE means that ½mv² + mg(d+x)sinΘ + ½...

3 Answers · Science & Mathematics · 09/11/2019

2. ### One last physics question?

... = ½ * 2kg * v² solves to v = 3.3 m/s b) convert SPE to GPE ½kx² = mgh = mgLsinΘ ½...

2 Answers · Science & Mathematics · 02/07/2019

3. ### Physics Question?

GPE becomes SPE mgh = ½kh² k = 2mg / h = 2*96*9.81 / 192 = 9.81 N/m period...

3 Answers · Science & Mathematics · 14/04/2018

4. ### Physics homework?? I'm lost!!?

Initial GPE becomes SPE: mgh = ½kx² 2.200kg * 9.8m/s² * (ℓ + 0.17m) * ...

2 Answers · Science & Mathematics · 04/01/2018

... / 100N/m = 0.49 m After pulling down 0.0200 m, SPE = ½ * 100N/m * (0.51m)² = 13.005 J and after...

1 Answers · Science & Mathematics · 23/12/2017

6. ### Physics Help!?

GPE becomes SPE mgh = ½kx² so you need the mass m to proceed. My mass is...

1 Answers · Science & Mathematics · 20/12/2017

7. ### A 884 g block is released from rest at height h0 above a vertical spring with spring constant k = 570 N/m and negligible mass.?

(a) the work done on the spring is W = SPE = ½kx² = ½ * 570N/m * (0.140m)² = 5.59...

1 Answers · Science & Mathematics · 02/12/2017

8. ### A toy rocket is launched straight up by using a spring.?

Do you have to use kinematics or can you use energy conservation? SPE = gpe 1/2*k*x^2 = m*g*h h = k*x^2/(2*m*g) Plug in numbers...

1 Answers · Science & Mathematics · 01/05/2017

9. ### How much work is required to stretch the spring 3.5cm from its equilibrium position?

... into the Spring Potential Energy equation: SPE = 1/2kx² where k = 45 N/m and x = 0.035 m U can do this...

3 Answers · Science & Mathematics · 02/05/2017

10. ### A 68-kg fisherman in a 126-kg boat throws a package of mass m = 15 kg horizontally toward the right with a spe?

we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

2 Answers · Science & Mathematics · 02/05/2017