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  1. ... = ½ * 2kg * v² solves to v = 3.3 m/s b) convert SPE to GPE ½kx² = mgh = mgLsinΘ ½...

    2 Answers · Science & Mathematics · 02/07/2019

  2. GPE becomes SPE mgh = ½kh² k = 2mg / h = 2*96*9.81 / 192 = 9.81 N/m period...

    3 Answers · Science & Mathematics · 14/04/2018

  3. Initial GPE becomes SPE: mgh = ½kx² 2.200kg * 9.8m/s² * (ℓ + 0.17m) * ...

    2 Answers · Science & Mathematics · 04/01/2018

  4. ... / 100N/m = 0.49 m After pulling down 0.0200 m, SPE = ½ * 100N/m * (0.51m)² = 13.005 J and after...

    1 Answers · Science & Mathematics · 23/12/2017

  5. GPE becomes SPE mgh = ½kx² so you need the mass m to proceed. My mass is...

    1 Answers · Science & Mathematics · 20/12/2017

  6. (a) the work done on the spring is W = SPE = ½kx² = ½ * 570N/m * (0.140m)² = 5.59...

    1 Answers · Science & Mathematics · 02/12/2017

  7. Do you have to use kinematics or can you use energy conservation? SPE = gpe 1/2*k*x^2 = m*g*h h = k*x^2/(2*m*g) Plug in numbers...

    1 Answers · Science & Mathematics · 01/05/2017

  8. ... into the Spring Potential Energy equation: SPE = 1/2kx² where k = 45 N/m and x = 0.035 m U can do this...

    3 Answers · Science & Mathematics · 02/05/2017

  9. we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

    2 Answers · Science & Mathematics · 02/05/2017

  10. ...any point = total energy = kinetic energy + spring potential energy KE = 1/2*m*v^2 SPE = 1/2*k*x^2 1) KE = 1/4*Total Energy TE = 1/4...

    1 Answers · Science & Mathematics · 22/04/2017

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