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.... For a spring compression of "x," initial KE + GPE =

**SPE**means that ½mv² + mg(d+x)sinΘ + ½...3 Answers · Science & Mathematics · 09/11/2019

... = ½ * 2kg * v² solves to v = 3.3 m/s b) convert

**SPE**to GPE ½kx² = mgh = mgLsinΘ ½...2 Answers · Science & Mathematics · 02/07/2019

GPE becomes

**SPE**mgh = ½kh² k = 2mg / h = 2*96*9.81 / 192 = 9.81 N/m period...3 Answers · Science & Mathematics · 14/04/2018

Initial GPE becomes

**SPE**: mgh = ½kx² 2.200kg * 9.8m/s² * (ℓ + 0.17m) * ...2 Answers · Science & Mathematics · 04/01/2018

... / 100N/m = 0.49 m After pulling down 0.0200 m,

**SPE**= ½ * 100N/m * (0.51m)² = 13.005 J and after...1 Answers · Science & Mathematics · 23/12/2017

GPE becomes

**SPE**mgh = ½kx² so you need the mass m to proceed. My mass is...1 Answers · Science & Mathematics · 20/12/2017

(a) the work done on the spring is W =

**SPE**= ½kx² = ½ * 570N/m * (0.140m)² = 5.59...1 Answers · Science & Mathematics · 02/12/2017

Do you have to use kinematics or can you use energy conservation?

**SPE**= gpe 1/2*k*x^2 = m*g*h h = k*x^2/(2*m*g) Plug in numbers...1 Answers · Science & Mathematics · 01/05/2017

... into the Spring Potential Energy equation:

**SPE**= 1/2kx² where k = 45 N/m and x = 0.035 m U can do this...3 Answers · Science & Mathematics · 02/05/2017

we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

2 Answers · Science & Mathematics · 02/05/2017