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1. ### Help with a physics problem solving question?

...0.437kg * 9.8m/s² / 0.0100m = 428 N/m GPE becomes SPE: mg(h+x)² = ½kx² 0.437kg * 9.8m/s² * (0.200m + x...

1 Answers · Science & Mathematics · 25/11/2017

2. ### A 44.2 g pinball starts at the top of a frictionless pinball table inclined at 45.0°?

Change in energy = 0 Change in GPE + Change in SPE = 0 M*g*(hf - hi) + 1/2*k*(xf^2 - xi^2) = 0 Eliminate some ...

1 Answers · Science & Mathematics · 15/11/2016

3. ### Find the spring constant?

GPE gets transferred to SPE M*g*(h + x) = 1/2*k*x^2 k = 2*(m*g*(h+x))/x^2 Plug in numbers K = 936 N/m

1 Answers · Science & Mathematics · 14/11/2016

4. ### Work to Stretch a Spring?

...for a spring in its elastic range} 3.75 = k(0.156) k ≈ 24.0 N/m SPE = 1/2kx² {definition of Spring Potential Energy...

1 Answers · Science & Mathematics · 31/05/2016

5. ### How far will the spring stretch?

... = kx = 1410x 15.5 = 1410x x = 15.5/1410 = 0.0110 m = 1.10 cm ANS SPE = 1/2kx² = (0.5)(1410)(4.01E-2)² = 1.13 J ANS...

1 Answers · Science & Mathematics · 04/11/2015

...loss as spring is compressed let x = max compression (distance) of spring SPE = GPE of dropped height + spring compression distance 1/2kx² = mg...

1 Answers · Science & Mathematics · 27/04/2014

7. ### Tough Physics Question - Grade 12 - Kinematics/Forces/Energy all in one - Please show steps?

... KE of block/bullet combination = 1/2(8.345)V² = 4.1725V² SPE = 1/2kx² = (0.5)(76)(0.28)² = 2.9792 J by conservation of energy...

2 Answers · Science & Mathematics · 03/12/2013

8. ### How much work is required to stretch the spring 3.5cm from its equilibrium position?

... into the Spring Potential Energy equation: SPE = 1/2kx² {where k = 45 N/m and x = 0.035 m} U can do this...

1 Answers · Science & Mathematics · 04/11/2013

9. ### What is an explanation of potential energy?

...potential energy (EPE). Another common example is strain potential energy (SPE), like that in a stretched or compressed spring. Consider...

4 Answers · Science & Mathematics · 15/05/2013

10. ### A 50.0 kg skier starts at A with an unknown initial speed, skis over a hill which is part of a circle?

...1/2 mv^2 = 1/2*50*23.6^2 = 13,924 J Spring potential energy: SPE = 1/2 k x^2 ----> 13,924 = 1/2*1820*x^2 Rearranging gives...

1 Answers · Science & Mathematics · 30/10/2011