##### Ads

related to: SPE

we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

2 Answers · Science & Mathematics · 02/05/2017

From your problem statement it sounds like you're only interested in the vertical dimension, and you also need to neglect the effect of aerodynamic drag. With these assumptions, right before the ball hits the ground it has converted...

2 Answers · Science & Mathematics · 15/07/2012

1 meter. .

2 Answers · Science & Mathematics · 18/12/2010

(a) translational kinetic energy = (1/2)*m*(v^2) =(1/2)*10*(10^2) =500J (b) rotational kinetic energy =(1/2)*I*(w^2) w-angular velocity(omega), I-moment of inertia =(1/2)*(2/5*m*r^2)(w^2...

2 Answers · Science & Mathematics · 24/12/2012

960mph. lol jk

2 Answers · Science & Mathematics · 10/08/2008

Don't forget to supply what units you are working with! (342 + 24.5) = apparent V of 366.5m/sec. a) (366.5/342) x 400 = 428.655Hz. b) 428.655Hz.

2 Answers · Science & Mathematics · 30/01/2013

When you driving at 45,6 m/s and you reduces your speed uniformly to 25.0 m/s you drive on the average 35.3 m/s In 4.20 s that is 148.26 m. So can also use the formal equations: a = (v1 - v0) / t. = (45.6 - 35.3)/4.2 and s = v0.t + (1/2).a.t^2 with s (at t=0) = 0...

1 Answers · Science & Mathematics · 06/10/2010

average v = (0 + 340) / 2 = 170 m/s Time in the barrel t = 0.85 / average v = 0.85 / 170 = 0.005 a = dv / dt = 340 / 0.005 = 68000 m/s2 force exerted on the rifle by the bullet F = m * a = 20 10^-3 * 68 10^3 = 1360 N Goodbye

1 Answers · Science & Mathematics · 13/02/2013

Q = m * Cp * dT Heat = mass * Specific Heat * Temperature Change 1635J = 2000g * Cp * 3K Cp = 1635/(2000 * 3) 0.2725 J/(g*K) or 272.5 J/(kg*K)

1 Answers · Science & Mathematics · 28/09/2008

height=initial velocity times time --1/2gravity times time squared h=2t-4.905t^2 you need to find the time when the velocity is zero 0=v-at t=.204 seconds plug it back in to the first equation h=2(.204)-4.905(.204)^2 h=.204 meters

1 Answers · Science & Mathematics · 04/10/2011

##### Ads

related to: SPE