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(a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

1 Answers · Science & Mathematics · 14/10/2013

By I = ∆P = m∆v =>9.87 = 0.54 x ∆v =>∆v = 18.28 m/s

1 Answers · Science & Mathematics · 21/10/2013

(2m/s) / (9.81m/s^2) = 0.204s He will start to fall down after 0.204 seconds, this is the moment where he will be the highest. d=-(a/2)t^2+vt d is how much the center of mass is raised, a is acceleration, v is initial velocity, t is time d=-(9.81/2)t^2...

1 Answers · Science & Mathematics · 07/12/2010

that... doesn t seem to be a valid question. First, there s no units, so it s impossible to answer it for that reason alone. Second, if you want units of work, what you need is force and distance, not speed. W = FD And power is Work per unit time so...

1 Answers · Science & Mathematics · 15/01/2009

When you driving at 45,6 m/s and you reduces your speed uniformly to 25.0 m/s you drive on the average 35.3 m/s In 4.20 s that is 148.26 m. So can also use the formal equations: a = (v1 - v0) / t. = (45.6 - 35.3)/4.2 and s = v0.t + (1/2).a.t^2 with s (at t=0) = 0...

1 Answers · Science & Mathematics · 06/10/2010

Momentum is conserved; the initial momentum of the system is zero, as is the final momentum: m*V = M*v → v = V*m/M = 4.1*15/188 v = 0.327 m/s

1 Answers · Science & Mathematics · 03/12/2012

Q1 = m1.c1.T1 Q2 = m2.c2.T2 ▬▬▬ Q3 = (m1.c1 + m2.c2)T3 = Q1 + Q2 → T3 = (m1.c1.T1 + m2.c2.T2)/(m1.c1 + m2.c2) → T3 = (0,39*230*98 + 0,26*4186*11,6)/(0,39*230 + 0,26*4186) = 18,2 °C @+ ;)

1 Answers · Science & Mathematics · 09/08/2011

Hello the centrifugal force = mv^2/R = 60*20^2/70 = 342,86 N the weight = mg = 60*9,81 = 588,6 N Difference = 245,74 N = weight on top ------ the acceleration would be a = mv^2/(R*m) = v^2/R = 400/70 = 5,714 m/s^2 and F = m(g - a) = 60(9,81 - 5,714) = 60*4,09 = 245...

1 Answers · Science & Mathematics · 18/05/2011

You need to use terminal velocity ideas. Check this link: http://en.wikipedia.org/wiki/Stokes%27_law Hope this helps. your_guide123@yahoo.com

1 Answers · Science & Mathematics · 18/11/2012

m1 v1 + m2 v2 = m1 u1 + m2 u2 m1 = 69 + 133 = 202 kg m2 = 15 kg v1 = v2 = 0 u2 - u1 = 4.4 m/s u2 = u1 + 4.4 m1 v1 + m2 v2 = m1 u1 + m2 u2 0 = 202 u1 + 15 (u1 + 4.4) 0 = 202 u1+ 15 u1 + 66 -66 = 217 u1 u1 = -66/217 = -0.304 m/s (it negative because the direction is opposed the package direction)

1 Answers · Science & Mathematics · 14/03/2013

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